msk0657 wrote:

EBITDA wrote:

What is the value of integer n if (√(16/(10^n)))^2 = 0.04^2

A) 0

B) 1

C) 2

D) 3

E) 4

Please explain in detail your answer.

Thank you.

Given (√(16/(10^n)))^2 = 0.04^2.

Now on LHS we can get rid of square root due to the square.

Then it becomes

=> (16/(10^n) = 0.0016

16 * 0.001 = 0.0016Cancelling 16 on both sides we get the below.

Now it changes to 1/\(10^n\) = 0.001

Cross multiplying

1/ 0.001 = \(10^n\)

\(10^3\) = \(10^n\).

So n = 3.

Option D is the correct option.

Hi msk0657,

The part of your answer that I have marked in red is wrong.

It should be

16 * 0.0001 = 0.0016Nonetheless, here is my approach.

First, I eliminate the square root and the square.

16 / (10^n) = (4 / 100)^2 ---> 16 / (10^n) = 16 / 10,000

Then, I eliminate the 16.

1/ (10^n) = 1 / 10,000

This equals:

10,000 = 10^n

Therefore, n = 4.

Could someone please explain where am I making an error?

Thank you so much.