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Sir, we factorise a number into prime factors. In statement A, 15 is not a prime factor. So, how did you eliminate A?
Archit3110
value of m*n #1 45= 3^2*5^1 so m=1 and n=2 ; mn= 2 sufficient Or 15^1*3^1 mn =1 insufficient #2 9^(m−1)(n−2)=1 possible 9^0 so either m=1 or n=2 but value of m and n can be different if either of them is m=1 or n=2 or could be same as well m*n could vary insufficient From 1&2 M =1 n=2 IMO c
(1) right off the bat, i noticed it doesn't say m and n are integers. This leaves the door wide open for odd combinations of numbers to make the statement true. INSUFFICIENT (2) as long as m or n is 1 or 2 and the exponent equals 0, the other number can be anything. INSUFFICIENT
C -> (2) states that m or n has to be 1 or 2, and placing that condition on (1) forces the other number to a single value. SUFFICIENT
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