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27 Jan 2012, 16:39
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:36) correct
19%
(01:33)
wrong
based on 408
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What is the value of the integer n?
(1) n! = n × (n – 1)!
(2) n^3 + 3n^2 + 2n is divisible by 3
(1) n! = n × (n – 1)!
(2) n^3 + 3n^2 + 2n is divisible by 3
27 Jan 2012, 17:08
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What is the value of the integer n?
(1) n!=n*(n – 1)! --> n*(n – 1)! equals to n! itself, so we have n!=n!. Useless statement.
(2) n^3 + 3n^2 + 2n is divisible by 3 --> n(n^2+3n+2)=n(n+1)(n+2): we have the product of 3 consecutive integers, which is ALWAYS divisible by 3. Useless statement.
(1)+(2) Two useless statements. Not sufficient.
Answer: E.
(1) n!=n*(n – 1)! --> n*(n – 1)! equals to n! itself, so we have n!=n!. Useless statement.
(2) n^3 + 3n^2 + 2n is divisible by 3 --> n(n^2+3n+2)=n(n+1)(n+2): we have the product of 3 consecutive integers, which is ALWAYS divisible by 3. Useless statement.
(1)+(2) Two useless statements. Not sufficient.
Answer: E.
General Discussion
30 Aug 2019, 04:11
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Bunuel
enigma123
What is the value of the integer n?
(1) n! = n × (n – 1)!
(2) n^3 + 3n^2 + 2n is divisible by 3
For me its clear E as we can't find the value of n from either of the statement. but, as I don't have an OA I thought to double check with you guys.
(1) n! = n × (n – 1)!
(2) n^3 + 3n^2 + 2n is divisible by 3
For me its clear E as we can't find the value of n from either of the statement. but, as I don't have an OA I thought to double check with you guys.
What is the value of the integer n?
(1) n!=n*(n – 1)! --> n*(n – 1)! equals to n! itself, so we have n!=n!. Useless statement.
(2) n^3 + 3n^2 + 2n is divisible by 3 --> n(n^2+3n+2)=n(n+1)(n+2): we have the product of 3 consecutive integers, which is ALWAYS divisible by 3. Useless statement.
(1)+(2) Two useless statements. Not sufficient.
Answer: E.
I'm not really sure but isn't n!=n! will give 1 as an answer
