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# What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4

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Joined: 02 Sep 2009
Posts: 50078
What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4  [#permalink]

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03 Dec 2017, 00:16
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Difficulty:

45% (medium)

Question Stats:

56% (01:29) correct 44% (01:32) wrong based on 36 sessions

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What is the value of x?

(1) $$3x^2 + 8x + \frac{16}{3} = 0$$

(2) $$15x^2 + \frac{80}{3} = -40x$$

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Re: What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4  [#permalink]

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03 Dec 2017, 00:23
1
(1) 3x^2 + 8x + 16/3 = 0 can be rewritten as
9x^2 + 24x + 16 = 0.. OR (3x+4)^2 = 0
This gives us x=-4/3. Sufficient.

(2) 15x^2 + 80/3 = -40x can be rewritten as
15x^2 + 40x + 80/3 = 0 .. Dividing this by 5, we get
5x^2 + 8x + 16/3 = 0. This is same as the equation in statement 1, and will give us same value of x. Sufficient.

Re: What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 &nbs [#permalink] 03 Dec 2017, 00:23
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