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605-655 Level|   Algebra|      
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gmatbull
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 29 Nov 2012, 12:02
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45% (medium)

Question Stats:

68% (01:51) correct 32% (01:54) wrong based on 365 sessions

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What is the value of x?


(1) \(3x^2 + 8x + \frac{16}{3} = 0\)

(2) \(15x^2 + \frac{80}{3} = -40x\)
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D
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Bunuel
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 29 Nov 2012, 13:54
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What is the value of x?

(1) 3x^2 + 8x + 16/3 = 0 --> multiply by 3: \(9x^2+24x+16=0\) --> \((3x+4)^2=0\) --> \(x=-4/3\). Sufficient.

(2) 15x^2 + 80/3 = -40x --> multiply by 3/5: \(9x^2+16=-24x\) --> \(9x^2+24x+16=0\) --> \((3x+4)^2=0\) --> \(x=-4/3\). Sufficient.

Answer: D.
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 29 Nov 2012, 15:49
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0k, that's a perfect square.
Otherwise, I reduced to the standard quadratic form: ax^2 + bx + c and factorize.
9x^2 + 24x + 16 = 0
9x^2 + 12x + 12x + 16 = 0
3x(3x+4) + 4(3x+4)=0
(3x + 4)^2 = 0

Or,
x^2 + (8/3)x + (4/3)^2 = 0 [(8/3)^2 = 4*(1)(16/9)]
(x + 4/3)^2 = 0....x= -4/3
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 05 Apr 2016, 18:21
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gmatbull
What is the value of x?

(1) 3x^2 + 8x + 16/3 = 0
(2) 15x^2 + 80/3 = -40x
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1 can be rewritten as (3x+4)^2 so we can find X.
2. can be rewritten as:
45x^2 + 80 +120x = 0
divide by 5:
9x^2 + 16+24x=0
basically the same equation
we can factor out (3x+4)^2 = 0

D
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 27 Jul 2017, 08:35
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for those like me who did not find square immediately:

for equation in form:
\(ax^2+bx+c=0\)

has the unique solution if:
\(b^2-4ac=0\)

Be careful with the \(+\) and \(-\) signs though. I often have confused myself with signs.
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 03 Dec 2017, 00:23
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(1) 3x^2 + 8x + 16/3 = 0 can be rewritten as
9x^2 + 24x + 16 = 0.. OR (3x+4)^2 = 0
This gives us x=-4/3. Sufficient.

(2) 15x^2 + 80/3 = -40x can be rewritten as
15x^2 + 40x + 80/3 = 0 .. Dividing this by 5, we get
5x^2 + 8x + 16/3 = 0. This is same as the equation in statement 1, and will give us same value of x. Sufficient.

Hence D answer
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 13 Mar 2020, 06:26
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gmatbull
What is the value of x?


(1) \(3x^2 + 8x + \frac{16}{3} = 0\)

(2) \(15x^2 + \frac{80}{3} = -40x\)
Show more

Target question: What is the value of x?

Statement 1: 3x² + 8x + 16/3 = 0
Let's first eliminate the fractions by multiplying both sides of the equation by 3
When we do this, we get: 9x² + 24x + 16 = 0
Factor to get: (3x + 4)(3x + 4) = 0
So, it must be the case that 3x + 4 = 0
So, 3x = -4
x = -4/3
So, the answer to the target question is x = -4/3
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: 15x² + 80/3 = -40x
Let's first eliminate the fractions by multiplying both sides of the equation by 3
When we do this, we get: 45x² + 80 = -120x
Add 120x to both sides: 45x² + 120x + 80 =0
Divide both sides by 5 to get: When we do this, we get: 9x² + 24x + 16 = 0
This is the same equation we had in statement 1
So, the answer to the target question is x = -4/3
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer: D

Cheers,
Brent
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 15 Oct 2021, 06:22
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gmatbull
What is the value of x?
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(1) \(3x^2 + 8x + \frac{16}{3} = 0\)
9x^2 +24x+ 16 =0

upon solving we get x=-4/3
Clearly sufficient

(2) \(15x^2 + \frac{80}{3} = -40x\)

9x^2 +24X +16=0
same eqn same x value

THerefore IMO D
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What is the value of x? (1) 3x^2 + 8x + 16/3 = 0 (2) 15x^2 + 80/3 = -4 17 Jan 2024, 06:36
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