What is the value of x? (1) (x^2+3)^2 - 11(x^2+3) + 28 = 0

If short of time, the logical answer will be E.

Statement 1 will give 4 values of x.
Statement 2 will give 2 values.
Insufficient

However, it may be possible that the two values of statement 2 are same in some cases or there is only one common value of x in the two statements. Therefore, time provided, check for the values.
Here, clearly there are two different values of x in statement 2. But we cannot say whether both values of x of statement 2 are in statement 1 too. Either C or E in such cases.


Algebraic

(1) \((x^2+3)^2 - 11(x^2+3) + 28 = 0\)
Take \(x^2+3\) as y, so \(y^2-11y+28=0.\)
\((y-7)(y-4)=0\). Thus, y is 4 or 7.
If y=4, then \(x^2+3=4.....x^2=1\) or x=1 or -1
If y=7, then \(x^2+3=7.....x^2=4\) or x=2 or -2
Insufficient

(2) \(x^2 + x - 2 = 0\)
\((x+2)(x-1)=0\)
x=1 or -2
Insufficient

Combined,
x can still be 1 or -2.


E