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28 Mar 2022, 01:30
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
72% (01:57) correct
28%
(02:01)
wrong
based on 68
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of x?
(1) \((x^2+3)^2 - 11(x^2+3) + 28 = 0\)
(2) \(x^2 + x - 2 = 0\)
(1) \((x^2+3)^2 - 11(x^2+3) + 28 = 0\)
(2) \(x^2 + x - 2 = 0\)
29 Mar 2022, 00:25
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Bunuel
If short of time, the logical answer will be E.
Statement 1 will give 4 values of x.
Statement 2 will give 2 values.
Insufficient
However, it may be possible that the two values of statement 2 are same in some cases or there is only one common value of x in the two statements. Therefore, time provided, check for the values.
Here, clearly there are two different values of x in statement 2. But we cannot say whether both values of x of statement 2 are in statement 1 too. Either C or E in such cases.
Algebraic
(1) \((x^2+3)^2 - 11(x^2+3) + 28 = 0\)
Take \(x^2+3\) as y, so \(y^2-11y+28=0.\)
\((y-7)(y-4)=0\). Thus, y is 4 or 7.
If y=4, then \(x^2+3=4.....x^2=1\) or x=1 or -1
If y=7, then \(x^2+3=7.....x^2=4\) or x=2 or -2
Insufficient
(2) \(x^2 + x - 2 = 0\)
\((x+2)(x-1)=0\)
x=1 or -2
Insufficient
Combined,
x can still be 1 or -2.
E
29 Mar 2022, 00:40
Kudos
Bookmarks
IMO E
i. given Equation will generate 4 values of the "x" hence, insufficient
ii. given equation will generate 2 values of the "x" hence, insufficient
combining both, again we get two different values. hence E
i. given Equation will generate 4 values of the "x" hence, insufficient
ii. given equation will generate 2 values of the "x" hence, insufficient
combining both, again we get two different values. hence E
