Last visit was: 14 Dec 2024, 09:47 It is currently 14 Dec 2024, 09:47
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
brstorewala
Joined: 28 Feb 2003
Last visit: 02 May 2004
Posts: 50
Own Kudos:
Posts: 50
Kudos: 33
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
stolyar
Joined: 03 Feb 2003
Last visit: 06 May 2014
Posts: 1,012
Own Kudos:
Posts: 1,012
Kudos: 1,753
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
brstorewala
Joined: 28 Feb 2003
Last visit: 02 May 2004
Posts: 50
Own Kudos:
Posts: 50
Kudos: 33
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
ju_1
Joined: 07 May 2003
Last visit: 07 Jul 2003
Posts: 4
Own Kudos:
Location: Dallas
Posts: 4
Kudos: 98
Kudos
Add Kudos
Bookmarks
Bookmark this Post
plz explain how it is B.........
User avatar
brstorewala
Joined: 28 Feb 2003
Last visit: 02 May 2004
Posts: 50
Own Kudos:
Posts: 50
Kudos: 33
Kudos
Add Kudos
Bookmarks
Bookmark this Post
from statement 1,

if x = 0 both sides are equal
if x = 1 both sides are again equal {(-1)^3 = -1 & -1^3 = 1}

therefore x =0 or x = 1

from statement 2

x can only be zero because the square of a number other than zero cannot be negative. {(-1)^2 = 1 which is not equal to -(1)^2)}

therefore statement 2 is sufficient to say that x = 0

hope that helps
User avatar
bb
User avatar
Founder
Joined: 04 Dec 2002
Last visit: 13 Dec 2024
Posts: 39,369
Own Kudos:
Given Kudos: 21,581
Location: United States (WA)
GMAT 1: 750 Q49 V42
GPA: 3
Products:
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GMAT 1: 750 Q49 V42
Posts: 39,369
Kudos: 76,728
Kudos
Add Kudos
Bookmarks
Bookmark this Post
brstorewala
from statement 1,

if x = 0 both sides are equal
if x = 1 both sides are again equal {(-1)^3 = -1 & -1^3 = 1}

therefore x =0 or x = 1

from statement 2

x can only be zero because the square of a number other than zero cannot be negative. {(-1)^2 = 1 which is not equal to -(1)^2)}

therefore statement 2 is sufficient to say that x = 0

hope that helps



I agree about -(1)^2, but where did you get it?
we have only -x^2 and (-x)^2; is it the -x^2 ?

-=
User avatar
brstorewala
Joined: 28 Feb 2003
Last visit: 02 May 2004
Posts: 50
Own Kudos:
Posts: 50
Kudos: 33
Kudos
Add Kudos
Bookmarks
Bookmark this Post
yes it is -x^2

negative sign is not included in the power.
Moderators:
Math Expert
97874 posts
Senior Moderator - Masters Forum
3116 posts
GMAT Tutor
1930 posts