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Math Expert V
Joined: 02 Sep 2009
Posts: 64163
What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3  [#permalink]

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Difficulty:   45% (medium)

Question Stats: 64% (01:49) correct 36% (01:32) wrong based on 133 sessions

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What is the value of (x - 1)(y + 1) ?

(1) x + y = 4
(2) xy = 3

_________________
Director  D
Status: Learning stage
Joined: 01 Oct 2017
Posts: 950
WE: Supply Chain Management (Energy and Utilities)
Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3  [#permalink]

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Bunuel wrote:
What is the value of (x - 1)(y + 1) ?

(1) x + y = 4
(2) xy = 3

Individually insufficient.

combining, we have two values of both x and y for which (x - 1)(y + 1) will have two values.

hence, insufficient.
Ans (E)
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PKN

Rise above the storm, you will find the sunshine
Intern  B
Joined: 04 Jan 2018
Posts: 35
Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3  [#permalink]

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E

individual statements are insufficient.

we'll get two values of x and y
x =1,3 y=3,1

so the binomial has 2 values

so E
Math Expert V
Joined: 02 Sep 2009
Posts: 64163
Re: What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3  [#permalink]

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Bunuel wrote:
What is the value of (x - 1)(y + 1) ?

(1) x + y = 4
(2) xy = 3

_________________
GMAT Club Legend  V
Joined: 18 Aug 2017
Posts: 6299
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3  [#permalink]

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Bunuel wrote:
What is the value of (x - 1)(y + 1) ?

(1) x + y = 4
(2) xy = 3

#1: x+y= 4

x,y can be (1,3) ( 2,2,) (4,0)

insufficient

#2 xy=3
3,1 , 1/3*9 ... in sufficient

on combining we get (1,3 ) as the only number which would be sufficient .. IMO C

answer is C over E so because definite values of x & y are not sure and we get two value s in (x - 1)(y + 1) on substitution of (3,1) or (1,3) What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3   [#permalink] 24 Dec 2018, 02:09

# What is the value of (x - 1)(y + 1) ? (1) x + y = 4 (2) xy = 3  