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What is the value of x^2 - 2x - 14?

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Intern
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What is the value of x^2 - 2x - 14?  [#permalink]

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New post 11 Oct 2017, 21:53
5
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

52% (01:21) correct 48% (01:27) wrong based on 103 sessions

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What is the value of \(x^2 - 2x - 14\)?

1) x < 0
2) (x-5)(x+3) = 0
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Re: What is the value of x^2 - 2x - 14?  [#permalink]

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New post 11 Oct 2017, 23:24
1
(1) Insufficient
(2) both roots of x=-3;5 give the same value when substituted to equation in stimulus

Answer B.
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Re: What is the value of x^2 - 2x - 14?  [#permalink]

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New post 22 Oct 2017, 12:41
Why is the answer not D?

x^2 -2x - 14 has solutions x = 1 + sqrt(15) and 1 - sqrt(15) using the quadratic formula. Only one of the two solutions is negative, so isn't A sufficient as well?
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Re: What is the value of x^2 - 2x - 14?  [#permalink]

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New post 22 Oct 2017, 12:54
wewewe2 wrote:
Why is the answer not D?

x^2 -2x - 14 has solutions x = 1 + sqrt(15) and 1 - sqrt(15) using the quadratic formula. Only one of the two solutions is negative, so isn't A sufficient as well?



I was thinking the same way, please explain in detail anyone
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What is the value of x^2 - 2x - 14?  [#permalink]

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New post 22 Oct 2017, 13:12
2
jajanb wrote:
wewewe2 wrote:
Why is the answer not D?

x^2 -2x - 14 has solutions x = 1 + sqrt(15) and 1 - sqrt(15) using the quadratic formula. Only one of the two solutions is negative, so isn't A sufficient as well?



I was thinking the same way, please explain in detail anyone


Hi wewewe2 & jajanb

The question asks to find the value of the equation \(f(x)=x^2-2x-14\). we are not asked to calculate the roots of \(f(x)\)

it is not given that \(f(x)=0\) here, hence you cannot calculate the roots of the equation.

From statement 1 you get multiple values of \(x\), hence there will be multiple values of \(f(x)\). Insufficient

Statement 2: implies that \(x=-3\) or \(5\). in either case \(f(x)\) yields the same result i.e \(f(-3)=f(5)=1\). Hence sufficient

Option B
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What is the value of x^2 - 2x - 14? &nbs [#permalink] 22 Oct 2017, 13:12
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