jajanb wrote:

wewewe2 wrote:

Why is the answer not D?

x^2 -2x - 14 has solutions x = 1 + sqrt(15) and 1 - sqrt(15) using the quadratic formula. Only one of the two solutions is negative, so isn't A sufficient as well?

I was thinking the same way, please explain in detail anyone

Hi

wewewe2 &

jajanbThe question asks to find the value of the equation \(f(x)=x^2-2x-14\). we are not asked to calculate the roots of \(f(x)\)

it is not given that \(f(x)=0\) here, hence you cannot calculate the roots of the equation.

From

statement 1 you get multiple values of \(x\), hence there will be multiple values of \(f(x)\).

InsufficientStatement 2: implies that \(x=-3\) or \(5\). in either case \(f(x)\) yields the same result i.e \(f(-3)=f(5)=1\). Hence

sufficientOption

B