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What is the value of x^4y^2 - x^4y^2 ?

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What is the value of x^4y^2 - x^4y^2 ?  [#permalink]

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New post 24 Mar 2015, 04:48
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A
B
C
D
E

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  45% (medium)

Question Stats:

68% (01:31) correct 32% (01:52) wrong based on 141 sessions

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Re: What is the value of x^4y^2 - x^4y^2 ?  [#permalink]

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New post 24 Mar 2015, 06:47
Bunuel wrote:
What is the value of x^4y^2 - x^4/y^2 ?

(1) x = 2y

(2) y = 1


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(1) x = 2y
on substituting x=2y into \(x^4y^2 - x^4/y^2\) we will get an expression in Y . Not sufficient.

(2) At y = 1
\(x^4y^2 - x^4/y^2\) = 0 Sufficient. answer :B
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New post 24 Mar 2015, 06:52
x^4y^2 - x^4/y^2 ?

written in this form, we get
x^(4y^2) which is x^16y
(1) doesn't tell much
(2) from x^16y we substract x^4, since y^2 =1
I guess something is missing here..
it is not clear whether (x^4)*(y^2) or that 4y^2 is the exponent of x.
if it is the first option, then the answer is B
if it is the second one, then the answer is E.
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Re: What is the value of x^4y^2 - x^4y^2 ?  [#permalink]

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New post 24 Mar 2015, 12:16
1
On further simplification of the problem we get , x^(8y) - x^(8/y)

St 1 gives a unkown variable. Not Sufficient.
St 2 solves the unknown. Sufficient.

Answer: B
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Re: What is the value of x^4y^2 - x^4y^2 ?  [#permalink]

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New post 24 Mar 2015, 19:38
1
Bunuel wrote:
What is the value of x^4y^2 - x^4/y^2 ?

(1) x = 2y

(2) y = 1


Kudos for a correct solution.


Statement 1:
after substituting 2y for x, we are still left with y
Insufficient

Statement 2:
when y=1, the expression equates to 0
Sufficient

Answer: B
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Re: What is the value of x^4y^2 - x^4y^2 ?  [#permalink]

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New post 24 Mar 2015, 21:02
FightToSurvive wrote:
On further simplification of the problem we get , x^(8y) - x^(8/y)

St 1 gives a unkown variable. Not Sufficient.
St 2 solves the unknown. Sufficient.

Answer: B


hi,
you will have to check on the equation you get after simplifying...
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Re: What is the value of x^4y^2 - x^4y^2 ?  [#permalink]

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New post 25 Mar 2015, 00:27
1
X^4Y^2-x^4/Y^2

1. X=2Y; substituting values equation will be in one variable 2Y^4Y^2-2Y^4/Y^2, but value of y is still unknown, not sufficient

2. y=1, X^4-X^4=0; sufficient

Hence answer is B

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Re: What is the value of x^4y^2 - x^4y^2 ?  [#permalink]

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New post 30 Mar 2015, 04:34
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New post 22 Oct 2018, 12:42
Bunuel wrote:
What is the value of x^4y^2 - x^4/y^2 ?

(1) x = 2y

(2) y = 1

\(?\,\,\,\, = \,\,\,\,{x^4}{y^2} - {{{x^4}} \over {{y^2}}}\,\,\,\, = \,\,\,\,{x^4}\left( {{y^2} - {1 \over {{y^2}}}} \right)\)

\(\left( 1 \right)\,\,x = 2y\,\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {2,1} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,? = \,\,\,{2^{\,4}}\left( {1 - 1} \right) = 0 \hfill \cr
\,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {4,2} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,? = \,\,\,{4^{\,4}}\left( {4 - {1 \over 4}} \right) \ne 0\,\, \hfill \cr} \right.\)

\(\left( 2 \right)\,\,y = 1\,\,\,\,\, \Rightarrow \,\,\,\,\,\,?\,\, = \,\,{x^4} \cdot \left( {1 - {1 \over 1}} \right)\,\, = \,\,0\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{\rm{SUFF}}.\,\,\,\,\,\,\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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What is the value of x^4y^2 - x^4y^2 ?   [#permalink] 22 Oct 2018, 12:42
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