ishan261288 wrote:
dcummins wrote:
You don't need to do much work on either statement.
statement (1) x^2 < 25
x < 5 and x >-5
-5<x<5
There is a range of values x could take from -4 to 4. Therefore, insufficient
Statement (2) x^2 >9
x> 3
x<-3
-3<x<3
again, there is a range of values that x can take. Therefore, insufficient.
Combined
Lets combine the ranges
-5<x<-3
3<x<5
X can be 4 or -4 ASSUMING X is an integer - but we aren't told that it is!
If x =4 the absolute value spits out 10, if x = -4 it spits out 8 Therefore insufficient.
dcumminsYou mentioned that
Statement (2) x^2 >9
x> 3
x<-3
-3<x<3
again, there is a range of values that x can take. Therefore, insufficient.
if x is greater than 3 and less than -3 how can it lie in between -3 and 3, I think there is some problem with inequality sign, is it true in reverse?
Plus how did you combined the range to yield what you have written above?
Thanks
lol you made me question myself for a second..
INDEPENDENTLY you consider the inequality range given by each stem right?
So we independently consider what the values could be under each stem first.
Stem 1 says
X^2<25
so X<5 and X can be >-5
-5<x<5 is the range given by this stem
The second stem
x^2>9
so x>3 and x<-3
independently we can see that the range of values given by each is too vast, so we combine
Combined, we consider the constraints given.
To the left of zero:
We are told that x <-3 but x> -5, so logically, if X is an integer is has to be -4 in this range. So we say -5<x<-3 yea?
Second, To the right of zero:
We are told that x<5 but x>3, so again, we combining the positive range x must be equal to 4 when its positive, so we say 3<x<5
You can see that we aren't told whether x is positive or negative; thus, x can be two values -4 and 4 if it is an integer.
You could combine the 2 already combined statements to show that -5<x<-3<-2<-1<0<1<2<3<x<5
lpetroski**EDIT** I realise i combined the 3 and -3 in that second stem... simple omission when typing it up
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