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28 Oct 2019, 22:05
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B
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Difficulty:
15%
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Question Stats:
76% (00:50) correct
24%
(01:22)
wrong
based on 51
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What is the volume of a cube with surface area \(54x^2\)?
(A) \(9x^2\)
(B) \(27x^3\)
(C) \(81x^2\)
(D) \(81x^3\)
(E) \(729x^3\)
(A) \(9x^2\)
(B) \(27x^3\)
(C) \(81x^2\)
(D) \(81x^3\)
(E) \(729x^3\)
saukrit
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Status:Current student at IIMB
Affiliations: IIM Bangalore
Location: India
Concentration: General Management, Technology
Schools: IIMB EPGP'22 (A)
GMAT 1: 600 Q47 V26
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28 Oct 2019, 22:09
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IMO Answer is B
The surface area of cube = 6 * surface area of one face of the cube (since a cube has 6 faces)
The surface area of cube = 6 * surface area of one face of the cube (since a cube has 6 faces)
saukrit
Joined: 05 Jul 2018
Last visit: 02 Sep 2024
Posts: 378
Given Kudos: 325
Status:Current student at IIMB
Affiliations: IIM Bangalore
Location: India
Concentration: General Management, Technology
Schools: IIMB EPGP'22 (A)
GMAT 1: 600 Q47 V26
GRE 1: Q162 V149
GPA: 3.6
WE:Information Technology (Consulting)
Products:
28 Oct 2019, 22:11
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IMO Answer is B
The surface area of cube = 6 * surface area of one face of the cube (since a cube has 6 faces)
\(54 x^2= 6* 9x^2\)
Area of a single face of cube =\(9*x^2\) = a^2 (a= side of the cube)
a= 3x
Volume= \((3x)^3 = 27 x^3\)
Hence B
The surface area of cube = 6 * surface area of one face of the cube (since a cube has 6 faces)
\(54 x^2= 6* 9x^2\)
Area of a single face of cube =\(9*x^2\) = a^2 (a= side of the cube)
a= 3x
Volume= \((3x)^3 = 27 x^3\)
Hence B
