Last visit was: 08 Jul 2025, 10:42 It is currently 08 Jul 2025, 10:42
Home
GMAT
Messages
Tests
Schools
Events
Rewards
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
avatar
JJ2014
avatar
Joined: 06 Sep 2012
Last visit: 26 Aug 2013
Posts: 35
Own Kudos:
199
 [29]
Given Kudos: 42
Concentration: Social Entrepreneurship
Posts: 35
Kudos: 199
 [29]
What percent of the mixture is Solution X? 08 Dec 2012, 11:49
5
Kudos
Add Kudos
24
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

25% (medium)

Question Stats:

80% (01:46) correct 20% (02:07) wrong based on 639 sessions

History

Date
Time
Result
Not Attempted Yet
Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?

A) 20%
B) 44%
C) 50%
D) 80%
E) 90%

Can someone please also direct me to a page in gmatclub that has similar mixture problems? Thanks!
ShowHide Answer
Official Answer
D
Most Helpful Reply
User avatar
Jp27
User avatar
Joined: 22 Dec 2011
Last visit: 25 Dec 2013
Posts: 173
Own Kudos:
1,136
 [5]
Given Kudos: 32
Posts: 173
Kudos: 1,136
 [5]
What percent of the mixture is Solution X? 08 Dec 2012, 12:03
1
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
JJ2014
Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?

A) 20%
B) 44%
C) 50%
D) 80%
E) 90%

Can someone please also direct me to a page in gmatclub that has similar mixture problems? Thanks!

you can solve this by allegation method.
Given 22% of A is the final mixture; Sol X has 20% chemical A and Sol Y has 30 % of A. (you don't need Chemical B to solve when you r solving the problem using this method)

\(X / Y = (30-22 ) / (22-20)\)
\(X / Y = 8/2 = 4/1\)

So X and Y are in the ratio 4 : 1
Question asks percent of the mixture is Solution X.

So \(X / Total = 4/5 *100 = 80%\)

Cheers
General Discussion
User avatar
carcass
User avatar
Board of Directors
Joined: 01 Sep 2010
Last visit: 08 Jul 2025
Posts: 4,720
Own Kudos:
36,121
 [3]
Given Kudos: 4,812
Posts: 4,720
Kudos: 36,121
 [3]
What percent of the mixture is Solution X? 08 Dec 2012, 12:16
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
also you can solve this one with the concept of weighted average or balance point

you care about only of chemical A in both X and Y

\(20\)------- \(22\) ------------------------\(30\)

Now the difference between 20 and 22 = 2; between 22 and 30 = 8

So \(8y = 2 x\)

\(\frac{8}{2}\) \(=\)\(\frac{x}{y}\)
Our ratio is 2 and 8 and using the concept of unknown multiplier the sum is 10. Our X is 8 on a total of 10 so 80 %

much more difficult to say that to explain. In that way you can solve a question difficult like this in 30 seconds.

Also algebraic approach works fine, but this is a bit faster
User avatar
shreerajp99
User avatar
Joined: 06 Jun 2010
Last visit: 07 Dec 2013
Posts: 143
Own Kudos:
48
 [2]
Given Kudos: 151
Posts: 143
Kudos: 48
 [2]
What percent of the mixture is Solution X? 09 Dec 2012, 01:29
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Here you go:

seed-mixture-x-is-40-percent-ryegrass-and-60-more-problems-73381.html

mixtures-problems-102057.html
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 8 July 2025
Posts: 102,593
Own Kudos:
739,485
 [2]
Given Kudos: 97,451
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 102,593
Kudos: 739,485
 [2]
What percent of the mixture is Solution X? 09 Dec 2012, 06:31
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
JJ2014
Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?

A) 20%
B) 44%
C) 50%
D) 80%
E) 90%

Can someone please also direct me to a page in gmatclub that has similar mixture problems? Thanks!

22% of chemical A in X+Y grams of solution comes from 20% chemical A in solution X and 30% chemical A in solution Y, thus:

0.22(X + Y) = 0.2X + 0.3Y --> X = 4Y --> X/(X+Y)=4/5=0.8.

Answer: D.

Check out question banks for similar problems:
DS mixture problems: search.php?search_id=tag&tag_id=43
PS mixture problems: search.php?search_id=tag&tag_id=114

Hope it helps.
User avatar
greatps24
User avatar
Joined: 22 Nov 2010
Last visit: 23 Jan 2017
Posts: 201
Own Kudos:
504
 [2]
Given Kudos: 75
Location: India
GMAT 1: 670 Q49 V33
WE:Consulting (Telecommunications)
GMAT 1: 670 Q49 V33
Posts: 201
Kudos: 504
 [2]
What percent of the mixture is Solution X? 09 Mar 2013, 00:14
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
JJ2014
Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?

A) 20%
B) 44%
C) 50%
D) 80%
E) 90%

Can someone please also direct me to a page in gmatclub that has similar mixture problems? Thanks!

Focus on Chemical A:

X--------------------------------------Y
20%---------------------------------30%

--------------------22%-----------------

30 - 22= 8--------------------22-20 = 2

X:Y = 8:2 = 4:1.

Therefore, %age of X = 4/5 * 100 = 80%
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,788
Own Kudos:
12,484
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,788
Kudos: 12,484
 [1]
What percent of the mixture is Solution X? 02 Feb 2015, 13:11
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Hi All,

These types of mixture questions can typically be solved with a variety of approaches (the average formula, ratios, TESTing VALUES, TESTing THE ANSWERS, etc.). Here's the standard Weighted Average Formula approach:

Solution X = 20% chemical A
Solution Y = 30% chemical A

Mixture of the two solutions = 22% chemical A

X = number of ounces of Solution X
Y = number of ounces of Solution Y

(.2X + .3Y) / (X + Y) = .22

.2X + .3Y = .22X + .22Y
.08Y = .02X

We can multiply both sides by 100 to get rid of the decimals...

8Y = 2X

The question asks for the percentage of the new mixture that is Solution X....

8/2 = X/Y
4/1 = X/Y

80% X and 20% Y

Final Answer:
Show Spoiler
D

GMAT assassins aren't born, they're made,
Rich
User avatar
law258
User avatar
Joined: 05 Sep 2016
Last visit: 11 Oct 2020
Posts: 261
Own Kudos:
112
 [2]
Given Kudos: 283
Status:DONE!
Posts: 261
Kudos: 112
 [2]
What percent of the mixture is Solution X? 27 Oct 2016, 16:22
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
0.20x+(1-x)0.30 = 0.22
0.20x+0.30-0.30x=0.22
-0.10x=-0.08
x=4/5 = 80%
avatar
Joc456
avatar
Joined: 26 Jan 2016
Last visit: 08 May 2017
Posts: 75
Own Kudos:
51
 [1]
Given Kudos: 55
Location: United States
Schools: CBS '19 (D) Anderson '19 (A) Marshall '19 (A) Stern '19 (A)
GPA: 3.37
Schools: CBS '19 (D) Anderson '19 (A) Marshall '19 (A) Stern '19 (A)
Posts: 75
Kudos: 51
 [1]
What percent of the mixture is Solution X? 27 Oct 2016, 16:40
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
If the solution is 22% of A we know off the bat that the majority of the solution has to be X. We can eliminate A,B,C.

Solution X is 20% A and Y is 30

So X is 2 units from the combo and Y is 8 units away.

Ration of X:Y for solution A is 8:2
8/10=80%
User avatar
Kritisood
User avatar
Joined: 21 Feb 2017
Last visit: 19 Jul 2023
Posts: 492
Own Kudos:
1,217
Given Kudos: 1,090
Location: India
GMAT 1: 700 Q47 V39
Products:
My Reviews
GMAT 1: 700 Q47 V39
Posts: 492
Kudos: 1,217
What percent of the mixture is Solution X? 20 Apr 2020, 01:46
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Diagram approach

X-----Y
20---30
--22--
8----2
4:1

what percent of the mixture is Solution X = 4/5*100=80%
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 08 Jul 2025
Posts: 16,101
Own Kudos:
74,207
Given Kudos: 475
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,101
Kudos: 74,207
What percent of the mixture is Solution X? 13 Nov 2023, 23:38
Kudos
Add Kudos
Bookmarks
Bookmark this Post
JJ2014
Solution X is 20% chemical A and 80% chemical B by volume; Solution Y is 30% chemical A and 70% chemical B. If a mixture of X and Y is 22% chemical A, what percent of the mixture is Solution X?

A) 20%
B) 44%
C) 50%
D) 80%
E) 90%

Can someone please also direct me to a page in gmatclub that has similar mixture problems? Thanks!

Here are two videos that explain the concept behind this problem in detail:
https://www.youtube.com/watch?v=_GOAU7moZ2Q
https://www.youtube.com/watch?v=VdBl9Hw0HBg

or you can check out these posts:
https://anaprep.com/arithmetic-weighted-averages/
https://anaprep.com/arithmetic-mixtures/
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 37,347
Own Kudos:
1,008
Posts: 37,347
Kudos: 1,008
What percent of the mixture is Solution X? 27 Jan 2025, 04:57
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Bunuel
Math Expert
102593 posts
Krunaal
PS Forum Moderator
678 posts