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When 140 is divided by positive integer k, the remainder is k - 12

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When 140 is divided by positive integer k, the remainder is k - 12  [#permalink]

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New post 28 Mar 2020, 13:32
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When 140 is divided by positive integer k, the remainder is k - 12. Which of the following could be the value of k?

(A) 16
(B) 28
(C) 38
(D) 48
(E) 51

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Re: When 140 is divided by positive integer k, the remainder is k - 12  [#permalink]

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New post 28 Mar 2020, 13:57
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GMATPrepNow wrote:
When 140 is divided by positive integer k, the remainder is k - 12. Which of the following could be the value of k?

(A) 16
(B) 28
(C) 38
(D) 48
(E) 51


140 = ak + k -12, where a is a positive integer.
k ( a+ 1) = 152
k (a+1 )= 4 * 38 = 8 * 19

So, k will be 38. We can double check it (38*3) = 114, the remainder is (140 -114) = 26, which is 12 less than k.

C is the answer.
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Re: When 140 is divided by positive integer k, the remainder is k - 12  [#permalink]

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New post 28 Mar 2020, 13:58
1
GMATPrepNow wrote:
When 140 is divided by positive integer k, the remainder is k - 12. Which of the following could be the value of k?

(A) 16
(B) 28
(C) 38
(D) 48
(E) 51


140 = kQ + k - 2

K(Q+1) = 152 = 19*8 or 38*4 (Basically k(Q+1) has to have a multiple of 19)

The only 1 that has a multiple of 19 is C - 38

Answer - C
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Re: When 140 is divided by positive integer k, the remainder is k - 12  [#permalink]

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New post 28 Mar 2020, 15:27
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GMATPrepNow wrote:
When 140 is divided by positive integer k, the remainder is k - 12. Which of the following could be the value of k?

(A) 16
(B) 28
(C) 38
(D) 48
(E) 51


--ASIDE---------------
There's a nice rule that says, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3
------------------------

In this question, we're told that 140 divided by k leaves a remainder of k - 12.
Since we aren't told the quotient (Q), let's just say that the quotient is q
In other words, 140 divided by k equals q with remainder k - 12.

We can now apply the above rule to get: 140 = kq + (k - 12)
Add 12 to both sides of the equation to get: 152 = kq + k
Factor the right-hand side to get: 152 = k(q + 1)

IMPORTANT: 152 equals then product of k and (q + 1). Since k and (q + 1) are both integers, we now know that k is a divisor of 152

152 = (2)(2)(2)(19)
So, 38 aka (2)(19) is a possible value of k

Answer: C

Cheers,
Brent

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Re: When 140 is divided by positive integer k, the remainder is k - 12  [#permalink]

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New post 29 Mar 2020, 04:14
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GMATPrepNow wrote:
When 140 is divided by positive integer k, the remainder is k - 12. Which of the following could be the value of k?

(A) 16
(B) 28
(C) 38
(D) 48
(E) 51


Approach #2
One of the great things about Integer Properties questions is that they can often be solved by testing the answer choices
So, you should give yourself about 30 seconds to find a faster (algebraic) approach to this question, and if you don't come up with anything, start testing answer choices.

(A) 16
We get: when 140 is divided by 16, the remainder is 16-12 (aka 4)
Not true.
140 divided by 16 equals 8 with remainder 12.
Eliminate A

(B) 28
We get: when 140 is divided by 28, the remainder is 28-12 (aka 16)
Not true.
140 divided by 28 equals 5 with remainder 0.
Eliminate B

(C) 38
We get: when 140 is divided by 38, the remainder is 38-12 (aka 26)
True
140 divided by 38 equals 3 with remainder 26.

Answer: C

Cheers,
Brent
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When 140 is divided by positive integer k, the remainder is k - 12  [#permalink]

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New post 29 Mar 2020, 06:35
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GMATPrepNow wrote:
When 140 is divided by positive integer k, the remainder is k - 12. Which of the following could be the value of k?

(A) 16
(B) 28
(C) 38
(D) 48
(E) 51




When 140 is divided by k the remainder is k-12



Two Important take aways

1) k - 12 definitely GREATER or equal to 12 because remainder is always less than the divisor and minimum remainder is ZERO
2) 140 - (remainder) = 140 - (k-12) = 152 - k must be divisible by k but since k is divisible by k therefore 128 also must be divisible by k i.e. k is a factor of 152


152= 4*38

i.e. k must be 38

answer: Option C
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Re: When 140 is divided by positive integer k, the remainder is k - 12  [#permalink]

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New post 29 Mar 2020, 07:27
GMATPrepNow wrote:
When 140 is divided by positive integer k, the remainder is k - 12. Which of the following could be the value of k?

(A) 16
(B) 28
(C) 38
(D) 48
(E) 51


140modk = k-12

(A) 16
140mod16 = -4mod16 = 16-4 = 12 <>16-12=4
(B) 28
140mod28 = 0 <>28-12 = 16
(C) 38
140mod38= 26 = 38-12; COULD BE POSSIBLE VALUE OF k
(D) 48
140mod48 = 44 <>48-12 = 36
(E) 51
140mod51 = 38 <> 51 -12 = 39

IMO C
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Re: When 140 is divided by positive integer k, the remainder is k - 12   [#permalink] 29 Mar 2020, 07:27

When 140 is divided by positive integer k, the remainder is k - 12

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