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17 Sep 2017, 08:04
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D
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Difficulty:
65%
(hard)
Question Stats:
63% (02:02) correct
37%
(02:18)
wrong
based on 467
sessions
History
Date
Time
Result
Not Attempted Yet
When a positive integer "l" is divided by a positive integer "k", the remainder is 13. When the positive integer "r" is divided by a positive integer "a", the remainder is 34 and finally when the positive integer "g" is divided by "z", the remainder is 101. Which of the following is a possible value of k + a + z ?
1. 148
2. 150
3. 151
a) 1 and 2
b) 2 and 3
c) 1 and 3
d) 3 only
e) 1, 2 and 3
1. 148
2. 150
3. 151
a) 1 and 2
b) 2 and 3
c) 1 and 3
d) 3 only
e) 1, 2 and 3
ManishKM1
Current Student
Joined: 22 Apr 2017
Last visit: 03 Jan 2019
Posts: 81
Given Kudos: 75
Location: India
Schools: MBS '20 (D) ISB '19 (D) ESADE '20 (A) IIM (A)
GMAT 1: 620 Q47 V29
GMAT 2: 630 Q49 V26
GMAT 3: 690 Q48 V35
GPA: 3.7
17 Sep 2017, 08:27
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bkpolymers1617
K>13, a>34, z>101 as per quotient & remainder property.
Hence min value for K is 14, A is 35 & Z is 102 Hence, possible value for K+A+Z = 151(14+35+102). Hence D.
General Discussion
06 Feb 2019, 23:35
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Bookmarks
bkpolymers1617
Since division by k gives remainder 13, k >= 14
Since division by a gives remainder 34, a >= 35
Since division by z gives remainder 101, z >= 102
So k + a + z >= 14 + 35 + 102
k + a + z >= 151
So of the given values, only 151 satisfies this condition.
Answer (D)
