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19 Nov 2025, 11:32
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I'm doing a refresher after a few months so this might be silly, but I wanted to check,
This is beyond obvious instances like where they explicitly mention it in the questions x not equal to 3 and the denominator is x-3, or even cases like x>1/x where x is obviously not zero.
- When can I assume the denominator cannot be zero?
- When do I need to make sure the question confirms it?
This is beyond obvious instances like where they explicitly mention it in the questions x not equal to 3 and the denominator is x-3, or even cases like x>1/x where x is obviously not zero.
19 Nov 2025, 12:28
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Moving to a PS-suboforum (not sure if should move to Quant Bunuel )
20 Nov 2025, 04:22
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DrMock
If you are given something like 1/(x-3) < 0, then you can assume x is not 3, because if x were 3 the expression would be undefined and couldn’t satisfy the inequality. But if the question asks you to find a range for x in an expression that has a denominator, then you must explicitly make sure the denominator is not zero when you derive that range. If you share the specific questions where this caused confusion, it would be easier to address the exact issue.
P.S. Move the topic to Main Quant forum. Thank you! bb
