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Director  Joined: 29 Aug 2005
Posts: 658
When integer m is divided by 13, the quotient is q and the r  [#permalink]

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Difficulty:   45% (medium)

Question Stats: 67% (02:01) correct 33% (02:20) wrong based on 948 sessions

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When integer m is divided by 13, the quotient is q and the remainder is 2. When m is divided by 17, the remainder is also 2. What is the remainder when q is divided by 17?

A. 0
B. 2
C. 4
D. 9
E. 13

Originally posted by seofah on 06 Apr 2009, 13:08.
Last edited by Bunuel on 29 Jan 2013, 04:16, edited 1 time in total.
Renamed the topic and added OA.
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botirvoy wrote:
When integer m is divided by 13, the quotient is q and the remainder is 2. When m is divided by 17, the remainder is also 2. What is the remainder when q is divided by 17?

A. 0
B. 2
C. 4
D. 9
E. 13

From the definition of quotients and remainders, we have:

m = 13q + 2
m = 17a + 2

(note that the quotient is different in the second case). So we have

13q + 2 = 17a + 2
13q = 17a

and since this equation involves only integers, the primes that divide the right side must divide the left, and vice versa. That is, q must be divisible by 17, and a must be divisible by 13. If q is divisible by 17, the remainder is zero when you divide q by 17.

Of course, if you can see that q = 17 is one possible value for q here, you can use that to get the answer of zero quickly as well.
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Senior Manager  Joined: 01 Mar 2009
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So q is 17 because if m = 13q + 2 and m is also 17(z)+2

So when 17 is divided by 17 the remainder is 0.

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Manager  Joined: 02 Mar 2009
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Got 0 as well but am I right in thinking that 0 is another possible value of q?
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shkusira wrote:
Got 0 as well but am I right in thinking that 0 is another possible value of q?

Yes, perfectly correct - and that makes the question quite easy!
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Director  Joined: 23 May 2008
Posts: 592

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m-13q=2
m-17s=2

13q=17s

r=0

A
Manager  Joined: 14 Nov 2008
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IanStewart wrote:
shkusira wrote:
Got 0 as well but am I right in thinking that 0 is another possible value of q?

Yes, perfectly correct - and that makes the question quite easy!

Thanks. Just to add, if q=0, it is divisible by 17.. and hence would not leave any remainder.
Intern  Joined: 10 May 2010
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1
We can solve this using a simple equation and deriving the values:-
m = 13q + 2 - 1
m = 17p + 2 - 2

=> 13q + = 17p + 2
=> 13q = 17p
=> q = 17p/3
Here, 17p is equal to (m-2) from eqn 2.
Therefore, q = (m-2)/3

Now substituting the values in eqn 1:-
=> m = 13(m-2)/3 + 2
From here, m = 2.

Now using M, the value of Q can be derived from eqn 1.
=> 2 = 13q + 2
=> q = 0

Now if we divide Q by any number henceforth, the remainder would always be 0.
Manager  Joined: 05 Feb 2007
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So, I understand how to get to here

m=(13q)+2
m=(17x)+2

13q=17x

But, once I reduce the equation to 13q=17x, I am unable to make any deductions...can someone provide a clear explanation on how to use algebra to derive the values when we still have variables?
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13q = 17p
lcm = 13 * 17.

thus q = 17.

hence remainder = 0
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amit2k9 wrote:
13q = 17p
lcm = 13 * 17.

thus q = 17.

hence remainder = 0

Careful here; if 13q = 17p, all you can say is that q is a multiple of 17, and that p is a multiple of 13. There is no way to find the actual value of q or p, and you certainly cannot be sure that q=17. It could be that q=34 and p=26, for example.

In general, if you see an equation like 13q = 17p, and if q and p are integers, then 13q and 17p are *the same number*. So they must have the same divisors. Since 17 is a divisor of 17p, it must be a divisor of 13q, so q must be divisible by 17.

Alternatively you can rewrite the equation as p = 13q/17, and since p is an integer, 13q/17 must be an integer, from which again we have that 13q is divisible by 17, so q is divisible by 17.
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Intern  Joined: 18 Dec 2012
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Can't I just say q=0, so
(1) m=13q+2 => m=13*0+2 <=> m=2
(2) m=17k+2 => 2=17k+2 <=> k=0
--> 0 divided by 17 will obviously result in a reminder of 0
Intern  B
Joined: 10 Dec 2012
Posts: 41
Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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Hi stewart,

Can this be the alternative approach?

m=13q+2
2=13(0)+2
15=13(1)+2
28=13(2)+2

and

m=17p+2
2=17(0)+2
19=17(1)+2
36=17(2)+2

Thus we know p=q and that's 0, so 0/17 = 0.
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Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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jaspreets wrote:
Hi stewart,

Can this be the alternative approach?

m=13q+2
2=13(0)+2
15=13(1)+2
28=13(2)+2

and

m=17p+2
2=17(0)+2
19=17(1)+2
36=17(2)+2

Thus we know p=q and that's 0, so 0/17 = 0.

Yes, you are correct in your approach. This question can be solved either by algebra as shown by Ian above or by plugging a few values as you have done. The trick here is to realise that you are finding a number that gives a remainder of 2 with both 13 and 17.
Intern  B
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Posts: 41
Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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Thank You Engr2012 for the rapid response. Appreciated Manager  S
Joined: 04 Jun 2015
Posts: 79
Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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seofah wrote:
When integer m is divided by 13, the quotient is q and the remainder is 2. When m is divided by 17, the remainder is also 2. What is the remainder when q is divided by 17?

A. 0
B. 2
C. 4
D. 9
E. 13

Here's my take on this-

We are given $$\frac{m}{13}$$ = q (rem 2)
and $$\frac{m}{17}$$ = _ r 2

One possible value for m that satisfies both the conditions is $$m = 2$$.
When $$m = 2$$, $$q$$ will be $$0 (\frac{2}{13}$$ gives quotient $$q= 0$$ and rem r= 2), which follows $$\frac{0}{17} = 0$$
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Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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seofah wrote:
When integer m is divided by 13, the quotient is q and the remainder is 2. When m is divided by 17, the remainder is also 2. What is the remainder when q is divided by 17?

A. 0
B. 2
C. 4
D. 9
E. 13

m=2+(13*17)=223
q=223/13=17
17/17 gives remainder of 0
A
Manager  S
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Posts: 88
Location: India
Concentration: Finance, Entrepreneurship
GMAT 1: 660 Q48 V32 Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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How do we know that when m is divided by 17 the quotient is different?
Math Expert V
Joined: 02 Sep 2009
Posts: 58390
Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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Bounce1987 wrote:
How do we know that when m is divided by 17 the quotient is different?

You'd get the same answer if you set them equal: 13q + 2 = 17q + 2 --> q = 0 --> remainder when dividing 0 by 17 is 0.

So, the quotients might or might not be the same but in any case you should consider more general case and denote them with different variables.
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Re: When integer m is divided by 13, the quotient is q and the r  [#permalink]

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_________________ Re: When integer m is divided by 13, the quotient is q and the r   [#permalink] 15 Oct 2018, 13:07
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