gracie
When integer x is divided by 4 and integer y is divided by 5, the remainder is 1 and the difference between quotients is 6. What is the sum of x and y?
A. 117
B. 119
C. 126
D. 137
E. 143
x=4(z+6)+1
y=5z+1
We are looking for x+y
x+y=4z+24+1+5z+1=9z+26
Ofcourse there will not be one value but it will depend on z and therefore the question should be " what CAN be the sum of X and y?"
So x+y=9z+26.......x+y-26=9z
Therefore any choice subtracted by 26 should be a multiple of 9..
Let's see the choices
A. 117..... 117-26=91....no
B. 119.....119-26=93...no
C. 126..... 126-26=100...no
D. 137....... 137-26=111.. no
E. 143......143-26=117..yes
So E
A short cut would be X+y-26 means addition of all digits should be divisible by 9
26 gives -(2+6)=-8, so any choice which gives (sumof digits -8) as 0 or a multiple of 9
117=1+1+7=9....9-8=1
119=1+1+9=11...11-8=3
126=1+2+6=9...9-8=1
137=1+3+7=11...11-8=3
143=1+4+3=8...8-8=0...yes
So 143 is the answer