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25 Dec 2015, 10:31
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Which of the following cannot be the median of five positive integers a, b, c, d, and e?
(A) a
(B) d + e
(C) b + c + d
(D) (b + c + d) / 3
(E) (a + b + c + d + e) / 5
Sent from my iPhone using Tapatalk
(A) a
(B) d + e
(C) b + c + d
(D) (b + c + d) / 3
(E) (a + b + c + d + e) / 5
Sent from my iPhone using Tapatalk
25 Dec 2015, 20:22
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sara86
Which of the following cannot be the median of five positive integers a, b, c, d, and e?
(A) a
(B) d + e
(C) b + c + d
(D) (b + c + d) / 3
(E) (a + b + c + d + e) / 5
Sent from my iPhone using Tapatalk
(A) a
(B) d + e
(C) b + c + d
(D) (b + c + d) / 3
(E) (a + b + c + d + e) / 5
Sent from my iPhone using Tapatalk
Hi,
lets see the choices one by one..
(A) a
if the numbers in ascending order are d,e,a,b,c... a is the median
(B) d + e
if d and e are the two smallest numbers and say c =d+e, rest a and b are the largest two numbers or equal to c..
ascending order will be.. d,e,c,a,b.. or d,e,d+e,a,b.... d+e is the median
(C) b + c + d..
since there are 5 numbers, third number will be the median, so an integer equal to sum of three integers cannot be the median..
b+c+d will be bigger than atleast three positive integers b,c, and d.. so b+c+d cannot be the median
(D) (b + c + d) / 3
alet a be the smallest, e be the largest and b,c,d be same positive int.. (b + c + d) / 3 will be the median
(E) (a + b + c + d + e) / 5
let all numbers be same or the average of numbers be same as the median.. (a + b + c + d + e) / 5 will be the median
ans C
25 Dec 2015, 21:39
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sara86
Which of the following cannot be the median of five positive integers a, b, c, d, and e?
(A) a
(B) d + e
(C) b + c + d
(D) (b + c + d) / 3
(E) (a + b + c + d + e) / 5
Sent from my iPhone using Tapatalk
(A) a
(B) d + e
(C) b + c + d
(D) (b + c + d) / 3
(E) (a + b + c + d + e) / 5
Sent from my iPhone using Tapatalk
Note that you are not given that the numbers are arranged in ascending order. They could be any way when arranged in ascending order. Keeping this in mind, try to find easy ways of getting the median.
(A) a
a could be the middle number
(B) d + e
Middle number could be other than d and e and d and e could be the numbers smaller than the middle numbers e.g.
1 , 1, 2, 2, 2
- Median is 2 which is 1 + 1
(D) (b + c + d) / 3
Avg of 3 numbers can certainly be the median - say all numbers are equal: 2, 2, 2, 2, 2 - median is 2 - avg of any 3 numbers
(E) (a + b + c + d + e) / 5
Avg of all 5 numbers can certainly be the median - say all numbers are equal: 2, 2, 2, 2, 2 - median is 2 - avg of all 5 numbers
(C) b + c + d
Now, you don't need to worry about (C) and you can just mark it but note why it cannot be the median.
Out of 5 positive numbers, median will be the middle number. b , c or d cannot be the middle number. So either a or e will be the median. Two numbers will be smaller than (or equal to) the median and two numbers will be greater (or equal to). So even if you pick both numbers which are smaller than the median, you will still need to pick one which is equal or greater. So sum of 3 numbers will certainly be greater than the median.
Answer (C)
