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Which of the following describes all values of x such that \(\frac{x + 2}{x - 3} < -4\)?
A. -3 < x < 2
B. 2 < x < 3
C. -2 < x < 3
D. -3 < x < -2
E. x > 2
\(\frac{x + 2}{x - 3} < -4\)
\(\frac{x + 2}{x - 3} + 4 <0\)
\(\frac{x + 2 + 4(x - 3)}{x - 3}<0\)
\(\frac{5x - 10}{x - 3}<0\)
\(\frac{x - 2}{x - 3}<0\)
The transition points are x = 2 and x = 3 (transition points are the values of x for which the numerator or denominator equals 0). This gives us three ranges:
\(x < 2\)
\(2 < x < 3\)
\(x > 3\)
Next, test an extreme value for x: if x is a large enough number, say 10, then both the numerator and the denominator will be positive, resulting in a positive value for the whole expression. Therefore, when x > 3, the expression is positive. Now, here’s the trick: since the expression is positive in the 3rd range, it will be negative in the 2nd range and positive again in the 1st range, following the pattern: +, -, +. Thus, the expression is negative for \(2 < x < 3\).
Answer: B.
Check the highlighted links below for the trick described above:
9. Inequalities
For more check Ultimate GMAT Quantitative Megathread
Hope it helps.