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Ekland
Joined: 15 Oct 2015
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Concentration: Finance, Strategy
Schools: Alberta"19 Fordham '18 Schulich Jan '18 Desautels '19 Haskayne(Calgary) Jindal '19 Owen '19 Olin '19 (I) Queens"18
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WE:Account Management (Education)
16 Feb 2016, 02:43
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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74% (01:08) correct
26%
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Which of the following equations forms the solution set for all real numbers that are 6 units away from -4?
\(|{x + 4}| = 6\)
\(|{x - 4}| = 6\)
\(|{x + 6}| = 4\)
\(|{x - 6}| = 4\)
\(|{x + 6}| = -4\)
\(|{x + 4}| = 6\)
\(|{x - 4}| = 6\)
\(|{x + 6}| = 4\)
\(|{x - 6}| = 4\)
\(|{x + 6}| = -4\)
16 Feb 2016, 03:02
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Nez
6 units away from -4 are two numbers -4 + 6 = 2 and -4 - 6 = -10.
Both, 2 and -10, are the roots of only the first equation:
\(|{x + 4}| = 6\) --> \(x + 4= 6\), so \(x = 2\) or \(x + 4= -6\), so \(x = -10\).
Answer: A.
General Discussion
Senthil1981
Joined: 23 Apr 2015
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22 Aug 2016, 20:45
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Nezdem
From the Statement : set for all real numbers that are 6 units away from -4 : x > 6-4 and < -6-4
-10 > x > 2
add 4 on both sides of the equation
= -6 > x+4 > 6 which is same as |x + 4| <6 answer is A)
+1 for kudos
