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Which of the following equations forms the solution set for all real n

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Which of the following equations forms the solution set for all real n [#permalink]

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New post 16 Feb 2016, 02:43
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Which of the following equations forms the solution set for all real numbers that are 6 units away from -4?

\(|{x + 4}| = 6\)

\(|{x - 4}| = 6\)

\(|{x + 6}| = 4\)

\(|{x - 6}| = 4\)

\(|{x + 6}| = -4\)
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Re: Which of the following equations forms the solution set for all real n [#permalink]

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New post 16 Feb 2016, 03:02
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Nez wrote:
Which of the following equations forms the solution set for all real numbers that are 6 units away from -4?

\(|{x + 4}| = 6\)

\(|{x - 4}| = 6\)

\(|{x + 6}| = 4\)

\(|{x - 6}| = 4\)

\(|{x + 6}| = -4\)


6 units away from -4 are two numbers -4 + 6 = 2 and -4 - 6 = -10.

Both, 2 and -10, are the roots of only the first equation:

\(|{x + 4}| = 6\) --> \(x + 4= 6\), so \(x = 2\) or \(x + 4= -6\), so \(x = -10\).

Answer: A.
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Re: Which of the following equations forms the solution set for all real n [#permalink]

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New post 22 Aug 2016, 20:45
Nezdem wrote:
Which of the following equations forms the solution set for all real numbers that are 6 units away from -4?

\(|{x + 4}| = 6\)

\(|{x - 4}| = 6\)

\(|{x + 6}| = 4\)

\(|{x - 6}| = 4\)

\(|{x + 6}| = -4\)



From the Statement : set for all real numbers that are 6 units away from -4 : x > 6-4 and < -6-4

-10 > x > 2
add 4 on both sides of the equation
= -6 > x+4 > 6 which is same as |x + 4| <6 answer is A)



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Re: Which of the following equations forms the solution set for all real n [#permalink]

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New post 30 Mar 2018, 14:41
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Re: Which of the following equations forms the solution set for all real n   [#permalink] 30 Mar 2018, 14:41
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