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I deduced this through a simple logic that if 3^16 is divisible by 3, then 3^16-1 is not divisible by 3. When you look at the options, only 24 is the option which needs 3^16-1 to be divisible by 3. Hence, it is definitely not divisible by 24. Is my approach correct or are there any gaps in this?
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Hi nuwaaanda,

Your approach is correct, and it's a sharp one. You've spotted the cleanest possible path to this question, so let me confirm the logic and point out the one small thing worth nailing down so the reasoning is airtight.

Your core insight is right.3^16 is a multiple of 3, so 3^16 - 1 sits one below a multiple of 3 - meaning it leaves a remainder of 2 when divided by 3, and is therefore never divisible by 3. Among the five choices, the only one that carries a factor of 3 is 24 (= 2^3 x 3). Since 3^16 - 1 has no factor of 3, it can't be divisible by 24. So C is the answer. That's exactly the right instinct.

The one gap to close. Your shortcut quietly assumes two things - both true here, but worth verifying so you don't apply it blindly elsewhere:

- 24 is the only choice needing a factor of 3. Check the others: 2, 5, and 41 are primes with no 3 in them, and 40 = 2^3 x 5 has no 3 either. So yes, 24 is genuinely the unique choice that demands divisibility by 3. Good.
- The question guarantees exactly one "NOT a factor." Because the stem promises a single correct answer, ruling out 24 on the factor-of-3 test is enough - you don't have to prove the other four actually are factors. (They are, via 3^16 - 1 = (3^2 - 1)(3^2 + 1)(3^4 + 1)(3^8 + 1) = 8 x 10 x 82 x 6562, which supplies the 2, 5, and 41 - but you didn't need that to pick C.)

Quick habit to lock it in. Whenever you use "this choice needs a factor the number doesn't have," do one fast scan: is that factor unique to this choice? If two choices needed a factor of 3, the shortcut alone wouldn't separate them. Here it does, so your method is both valid and complete.

Answer: C

nuwaaanda
I deduced this through a simple logic that if 3^16 is divisible by 3, then 3^16-1 is not divisible by 3. When you look at the options, only 24 is the option which needs 3^16-1 to be divisible by 3. Hence, it is definitely not divisible by 24. Is my approach correct or are there any gaps in this?
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