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Which of the following is the lowest positive integer that
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Updated on: 10 Jan 2013, 15:23
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Which of the following is the lowest positive integer that is divisible by the first 7 positive integer multiples of 5? A. 140 B. 210 C. 1400 D. 2100 E. 3500
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Originally posted by sambam on 10 Jan 2013, 08:38.
Last edited by Bunuel on 10 Jan 2013, 15:23, edited 1 time in total.
Renamed the topic and edited the question.




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Which of the following is the lowest positive integer that
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10 Jan 2013, 15:27
sambam wrote: Which of the following is the lowest positive integer that is divisible by the first 7 positive integer multiples of 5?
A. 140 B. 210 C. 1400 D. 2100 E. 3500 The first 7 positive multiples of 5 are 5, 10, 15, 20, 25, 30 and 35. The least common multiple of these numbers is 2,100. Answer: D. Or, a shortcut approach: Discard 140, 1,400 and 3,500 because they are not divisible by 3. Discard 210 because it's not divisible by 4. Only option D remains.
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Which of the following is the lowest positive integer that
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10 Jan 2013, 17:33
Why are we looking at divisibility by 3 and 4?



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Re: Which of the following is the lowest positive integer that
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10 Jan 2013, 17:53
hitman5532 wrote: Bunuel wrote: sambam wrote: Which of the following is the lowest positive integer that is divisible by the first 7 positive integer multiples of 5?
A. 140 B. 210 C. 1400 D. 2100 E. 3500 The first 7 positive multiples of 5 are 5, 10, 15, 20, 25, 30 and 35. The least common multiple of these numbers is 2,100. Answer: D. Or: Discard 140, 1,400 and 3,500 because they are not divisible by 3. Discard 210 because it's not divisible by 4. Only option D remains. Why are we looking at divisibility by 3 and 4? The least common multiple of 5, 10, 15, 20, 25, 30 and 35 must be a multiple of 3 since 15 is a multiple of 3 and it must a multiple of 4 since 20 is a multiple of 4. Hope it's clear.
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Re: Which of the following is the lowest positive integer that
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10 Jan 2013, 18:38
I knew I was missing something very simple. Thank you



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Re: Which of the following is the lowest positive integer that
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10 Jan 2013, 19:25
first 7 positive multiples of 5 are 5, 10, 15, 20, 25, 30 and 35. 5 = 1* 5 10 = 2 * 5 15 = 3 * 5 20 = 4 * 5 = \(2^2 * 5\) 25 = 5 * 5 = \(5 ^ 5\) 30 = 6 * 5= \(2*3*5\) 35 = 7* 5 So, LCM would be 1 * \(2^2\) * 3 * \(5^5\) * 7 = 2100 actually i made mistake while computing first after going through Bunuel soln i got above one
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Re: Which of the following is the lowest positive integer that
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10 Jul 2015, 04:02
honchos wrote: Which of the following is the lowest positive integer that is divisible by the first 7 positive integer multiples of 5? 140 210 1400 2100 3500 One way to look at it this : 1st 7 multiples of 5: 5 =1*5 10=2*5 15=3*5 20=4*5=2^2*5 25=5^2 30=2*3*5 35=5*7 Always try to break down the numbers into their corresponding prime factors. For LCM (least common multiple) take the highest powers of 2,3,5,7 which gives us : 2^2 *3*5^2*7 = 2100. Hence D is the correct answer.



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Re: Which of the following is the lowest positive integer that
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29 May 2017, 14:58
sambam wrote: Which of the following is the lowest positive integer that is divisible by the first 7 positive integer multiples of 5?
A. 140 B. 210 C. 1400 D. 2100 E. 3500 First write out in a single column the first seven positive multiples of 5: 5 10 15 20 25 30 35 Then in the next column write out their prime factors: 5 2*5 3*5 2^2*5 5^2 2*3*5 7*5 For an integer to be divisible by each of these prime groups, it must have all of these primes at their highest power. So it must have at least 5^2 for instance because 5^2 is 25 and this integer must be divisible by 25. We can narrow the list down to 5^2*7*2^2*3 100*7*3 100*21 = 2100.



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Re: Which of the following is the lowest positive integer that
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22 Jan 2018, 15:53
Hi All, This question has a few builtin Number Properties that you can take advantage of (and you can use the 5 answer choices to your advantage): We're looking for the SMALLEST positive integer that's divisible by 5, 10, 15, 20, 25, 30 and 35. 30 is divisible by 5, 10 and 15, so we don't have to 'find' any of those numbers in the final answer... we just have to make sure that 30 is divisible into it. Since 30 is divisible by 3, the final answer MUST also be divisible by 3. Using the 'rule of 3', you can quickly eliminate Answers A, C and E. Between the final two answers 2100 and 210, you should be able to easily see that 210 is NOT divisible by 25. Final Answer: GMAT assassins aren't born, they're made, Rich
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