Condon
chetan2u
Bunuel
Which of the following must be an integer if the integer x is divisible by both 18 and 21?
A. x/252
B. x/189
C. x/126
D. x/108
E. x/81
the integer has to be multiple of LCM of 18 and 21, which is 126..
so x/126 will be an integer
ans C
252 is also a multiple of both 18 and 21
I've seen a similar question being solved with primes but I am not sure how exacly:
18= 2 * 3^2
21= 3*7
Is it 2*3^2 *7?!
Can somebody explain this to me? Thanks
Hi,
the Q asks us 'must' be an integer....
we know x is div by 18 and 21, so to answer 'must' question, we take the worst scenario that x is the lowest common multiple..
say if x is 126, as per the conditions given..
will x/252 be an integer..NO
it will be 126/252=1/2.. so x/252 will not be always an integer, But the question asks us 'must' be an integer so it has to be always an int..
Hope it helps