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↧↧↧ Detailed Video Solution to the Problem Series ↧↧↧




B. \(\sqrt[4]{4}\) = \(\sqrt[2^2]{4}\) = \((2)^(\frac{2}{4})\) = \(\sqrt{2}\)

Now, we need to compare \(\sqrt{2}\), \(\sqrt[4]{4}\) and \(\sqrt[5]{5}\)

let's make the power integer for all of them for easier comparison.
We can do that by raising all the numbers by power of LCM of the denominators of the powers
=> LCM(2,3,5) = 2*3*5 = 30

=> We need to compare \((2)^(\frac{30}{2})\), \((3)^(\frac{30}{3})\) and \((5)^(\frac{30}{5})\)
=> We need to compare \(2^{15}\), \(3^{10}\) and \(5^6\)


1. Lets compare \(2^{15}\) and \(3^{10}\)
\(2^{(3*5)}\) and \(3^{(2*5)}\)
=> \(8^5\) and \(9^5\)
And we know that \(9^5\) > \(8^5\)
=> \(\sqrt[3]{3}\) > \(\sqrt[2]{2}\)

2. Lets compare \(2^{15}\) and \(5^6\)
\(2^{(5*3}\) and \(5^{(2*3)}\)
=> \(32^3\) and \(25^3\)
And we know that \(32^3\) > \(25^3\)
=> \(2^15\) > \(5^6\)

=> \(\sqrt[3]{3}\) > \(\sqrt[2]{2}\) > \(\sqrt[5]{5}\)

So, Answer will be A
Hope it helps!

Watch the following video to MASTER Roots

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