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Which one of the following equations has a root in common with m^2 + 4

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Which one of the following equations has a root in common with m^2 + 4  [#permalink]

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12 Nov 2018, 00:43
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15% (low)

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73% (00:51) correct 27% (00:37) wrong based on 94 sessions

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Which one of the following equations has a root in common with $$m^2 + 4m + 4 = 0$$ ?

A. $$m^2 − 4m + 4 = 0$$

B. $$m^2 + 4m + 3 = 0$$

C. $$m^2 − 4 = 0$$

D. $$m^2 + m − 6 =0$$

E. $$m^2 + 5m + 4 = 0$$

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Which one of the following equations has a root in common with m^2 + 4  [#permalink]

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12 Nov 2018, 01:38
Bunuel wrote:
Which one of the following equations has a root in common with $$m^2 + 4m + 4 = 0$$ ?

A. $$m^2 − 4m + 4 = 0$$

B. $$m^2 + 4m + 3 = 0$$

C. $$m^2 − 4 = 0$$

D. $$m^2 + m − 6 =0$$

E. $$m^2 + 5m + 4 = 0$$

root value of m^2 + 4m + 4 = 0 will be m=-2,-2

for m^2 − 4m + 4 = 0 , m= (2,2)
m^2 + 4m + 3 = 0[, m= (-3,-1)
m^2 − 4 = 0, m=+/-2
m^2 + m − 6 =0= m= -3,+2
m^2 + 5m + 4 = 0= , m= -3,-2

common root would be in option E and option C , i think option E would be correct...

GMATinsight : sir how is C correct?
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Re: Which one of the following equations has a root in common with m^2 + 4  [#permalink]

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13 Nov 2018, 04:32
Archit3110 wrote:
Bunuel wrote:
Which one of the following equations has a root in common with $$m^2 + 4m + 4 = 0$$ ?

A. $$m^2 − 4m + 4 = 0$$

B. $$m^2 + 4m + 3 = 0$$

C. $$m^2 − 4 = 0$$

D. $$m^2 + m − 6 =0$$

E. $$m^2 + 5m + 4 = 0$$

root value of m^2 + 4m + 4 = 0 will be m=-2,-2

for m^2 − 4m + 4 = 0 , m= (2,2)
m^2 + 4m + 3 = 0[, m= (-3,-1)
m^2 − 4 = 0, m=+/-2
m^2 + m − 6 =0= m= -3,+2
m^2 + 5m + 4 = 0= , m= -3,-2

common root would be in option E and option C , i think option E would be correct...

GMATinsight : sir how is C correct?

Archit3110

Your calculation is wrong here in option E

Option E : $$m^2 + 5m + 4 = (m+1)*(m+4) = 0$$ i.e. m = -1 or -4 hence no root common with given equation

Option C: $$m^2 − 4 = 0$$, m=+/-2 i.e. root m=-2 is common hence the CORRECT OPTION

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Which one of the following equations has a root in common with m^2 + 4  [#permalink]

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13 Nov 2018, 04:35
GMATinsight wrote:
Archit3110 wrote:
Bunuel wrote:
Which one of the following equations has a root in common with $$m^2 + 4m + 4 = 0$$ ?

A. $$m^2 − 4m + 4 = 0$$

B. $$m^2 + 4m + 3 = 0$$

C. $$m^2 − 4 = 0$$

D. $$m^2 + m − 6 =0$$

E. $$m^2 + 5m + 4 = 0$$

root value of m^2 + 4m + 4 = 0 will be m=-2,-2

for m^2 − 4m + 4 = 0 , m= (2,2)
m^2 + 4m + 3 = 0[, m= (-3,-1)
m^2 − 4 = 0, m=+/-2
m^2 + m − 6 =0= m= -3,+2
m^2 + 5m + 4 = 0= , m= -3,-2

common root would be in option E and option C , i think option E would be correct...

GMATinsight : sir how is C correct?

Archit3110

Your calculation is wrong here in option E

Option E : $$m^2 + 5m + 4 = (m+1)*(m+4) = 0$$ i.e. m = -1 or -4 hence no root common with given equation

Option C: $$m^2 − 4 = 0$$, m=+/-2 i.e. root m=-2 is common hence the CORRECT OPTION

GMATinsight
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Joined: 12 Sep 2017
Posts: 63
Re: Which one of the following equations has a root in common with m^2 + 4  [#permalink]

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12 Jan 2019, 18:35
Is it possible to solve this question via Vietes theorem?

Bunuel

Kind regards!
Re: Which one of the following equations has a root in common with m^2 + 4 &nbs [#permalink] 12 Jan 2019, 18:35
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