VeritasPrepKarishma wrote:
aselfmademan wrote:
With both inlets open, a water tank will be filled with water in 48 minutes. The first inlet alone would fill the tank in 2 hours. If in every minutes the second inlet admits 50 cubic meters of water than the first, what is the capacity of the tank ?
a)10,500
b)12,000
c)9,000
d)11,750
e)13,000
We know that rates are additive.
Rate of work of inlet 1 = (1/2) tank/hour = (1/120) tank/min
Rate of work of both together = 1/(48/60) = (5/4) tank/hour
Rate of work of inlet 2 alone = 5/4 - 1/2 = 3/4 tank/hour = 1/80 tank/min
We see that rate of work of inlet 2 is higher.
1/80 - 1/120 = 1/240 tank
This (1/240)th of the tank capacity is given as 50 cubic meters.
Total tank capacity = 50*240 = 12000 cubic meters
Hello Madam,
I have a doubt..... is this equation correct :
Assuming C as capacity
A as time taken by inlet 1 to fill the tank
B as time taken by inlet 2 to fill the tank.
\((\frac{C}{A}+\frac{C}{B})48=C\).........Is this correct ??
We know that inlet 1 takes 2hr or 120 mins to fill the tank
\((\frac{C}{120}+\frac{C}{B})48=C\)
Then
\((\frac{1}{120}+\frac{1}{B})48=1\)
B=80
I am taking C in the equation for better understanding and because as the rate is not given purely in terms of time taken , as a safer approach I used C.
Also madam as \(\frac{1}{80}-\frac{1}{120}=\frac{1}{240}\)
Can I say 1/240 is the rate difference between the two inlets and (1/240)1 = 50
i.e here 1/240 is the rate, time = 1 and 50 is work done.
Thanks