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# Working alone, Bud can complete a particular task in 6 hours. Lou, wor

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Working alone, Bud can complete a particular task in 6 hours. Lou, wor  [#permalink]

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Updated on: 03 May 2017, 21:07
1
00:00

Difficulty:

5% (low)

Question Stats:

84% (01:01) correct 16% (01:39) wrong based on 68 sessions

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Working alone, Bud can complete a particular task in 6 hours. Lou, working alone, can complete the same task in 8 hours. If Bud and Lou work together, how many hours will it take them to complete the task?

A. 7

B. 3$$\frac{4}{7}$$

C. 3$$\frac{1}{2}$$

D. 3$$\frac{3}{7}$$

E. 3

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Last edited by warriorguy on 03 May 2017, 21:07, edited 3 times in total.
Formatted using formula button
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Re: Working alone, Bud can complete a particular task in 6 hours. Lou, wor  [#permalink]

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03 May 2017, 11:45
1
Efficieny
Bud =1/6
Lou=1/8
Together= 1/6+1/8
=7/24
=3(3/7)
Option D

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Working alone, Bud can complete a particular task in 6 hours. Lou, wor  [#permalink]

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Updated on: 03 May 2017, 22:35
Bud can do the work in 6 hours and Lou can complete the work in 8 hours.
Lets assume the total number of units to be 48 units.
P.S Chosen the LCM of the two numbers 6,8

Hence, Bud does 8 units/hour and Lou does 6 units/hour

Together they do 14 units/hour, so to complete the entire work together
They will take 48 units/14 units/hour
= $$\frac{24}{7}$$ hours =3$$\frac{3}{7}$$ (Option D)

Another method

Bud does 1/6 of the work in an hour and Lou does 1/8 of the work in an hour
Together they do, 14/48 of the work in an hour(1/6 +1/8)
So, they take $$\frac{24}{7}$$ or 3$$\frac{3}{7}$$ hours to complete the work. (Option D)
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Originally posted by pushpitkc on 03 May 2017, 11:49.
Last edited by pushpitkc on 03 May 2017, 22:35, edited 1 time in total.
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Re: Working alone, Bud can complete a particular task in 6 hours. Lou, wor  [#permalink]

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03 May 2017, 21:05
1

It is easier to look at 3$$\frac{3}{7}$$ than 3(3/7)
Re: Working alone, Bud can complete a particular task in 6 hours. Lou, wor &nbs [#permalink] 03 May 2017, 21:05
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