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Working alone, Bud can complete a particular task in 6 hours. Lou, wor

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Working alone, Bud can complete a particular task in 6 hours. Lou, wor [#permalink]

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Question Stats:

75% (00:45) correct 25% (00:49) wrong based on 61 sessions

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Working alone, Bud can complete a particular task in 6 hours. Lou, working alone, can complete the same task in 8 hours. If Bud and Lou work together, how many hours will it take them to complete the task?

A. 7

B. 3\(\frac{4}{7}\)

C. 3\(\frac{1}{2}\)

D. 3\(\frac{3}{7}\)

E. 3
[Reveal] Spoiler: OA

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Last edited by warriorguy on 03 May 2017, 21:07, edited 3 times in total.
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Re: Working alone, Bud can complete a particular task in 6 hours. Lou, wor [#permalink]

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Efficieny
Bud =1/6
Lou=1/8
Together= 1/6+1/8
=7/24
Hours=24/7
=3(3/7)
Option D


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Working alone, Bud can complete a particular task in 6 hours. Lou, wor [#permalink]

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New post 03 May 2017, 11:49
Bud can do the work in 6 hours and Lou can complete the work in 8 hours.
Lets assume the total number of units to be 48 units.
P.S Chosen the LCM of the two numbers 6,8

Hence, Bud does 8 units/hour and Lou does 6 units/hour

Together they do 14 units/hour, so to complete the entire work together
They will take 48 units/14 units/hour
= \(\frac{24}{7}\) hours =3\(\frac{3}{7}\) (Option D)

Another method

Bud does 1/6 of the work in an hour and Lou does 1/8 of the work in an hour
Together they do, 14/48 of the work in an hour(1/6 +1/8)
So, they take \(\frac{24}{7}\) or 3\(\frac{3}{7}\) hours to complete the work. (Option D)
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Last edited by pushpitkc on 03 May 2017, 22:35, edited 1 time in total.
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Re: Working alone, Bud can complete a particular task in 6 hours. Lou, wor [#permalink]

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New post 03 May 2017, 21:05
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Please use the formula button.

It is easier to look at 3\(\frac{3}{7}\) than 3(3/7)
Re: Working alone, Bud can complete a particular task in 6 hours. Lou, wor   [#permalink] 03 May 2017, 21:05
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Working alone, Bud can complete a particular task in 6 hours. Lou, wor

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