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x^2 + bx + 16 = 0, b is constant. What is the value of x?

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SVP
Joined: 29 Aug 2007
Posts: 2426
x^2 + bx + 16 = 0, b is constant. What is the value of x? [#permalink]

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11 Dec 2008, 15:36
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x^2 + bx + 16 = 0, b is constant. What is the value of x?

(i) b>0
(ii) x^2+x+16=36

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Senior Manager
Joined: 21 Apr 2008
Posts: 265
Location: Motortown

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11 Dec 2008, 18:30
GMAT TIGER wrote:
x^2 + bx + 16 = 0, b is constant. What is the value of x?

(i) b>0
(ii) x^2+x+16=36

C

stmt2: You get x = 4 or -5 - In Suff
stmt1 : In Suff

Together

When you substitute 4 into the given euation b =0
So, x = -5
Manager
Joined: 27 May 2008
Posts: 192

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11 Dec 2008, 19:48
Agree with LiveStronger but with slight change

stmt2: You get x = 4 or -5 - In Suff
stmt1 : In Suff

sub x= 4 we get b = -8
and x = -5 we get b = 41/5

so b +ve only when x = -5.

--== Message from GMAT Club Team ==--

This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: DS: x=?   [#permalink] 11 Dec 2008, 19:48
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