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x^2 + bx + 16 = 0, b is constant. What is the value of x?

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SVP
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x^2 + bx + 16 = 0, b is constant. What is the value of x? [#permalink]

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New post 11 Dec 2008, 14:36
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x^2 + bx + 16 = 0, b is constant. What is the value of x?

(i) b>0
(ii) x^2+x+16=36
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Kudos [?]: 868 [0], given: 19

Senior Manager
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Re: DS: x=? [#permalink]

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New post 11 Dec 2008, 17:30
GMAT TIGER wrote:
x^2 + bx + 16 = 0, b is constant. What is the value of x?

(i) b>0
(ii) x^2+x+16=36


C

stmt2: You get x = 4 or -5 - In Suff
stmt1 : In Suff

Together

When you substitute 4 into the given euation b =0
So, x = -5

Kudos [?]: 168 [0], given: 0

Manager
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Kudos [?]: 48 [0], given: 0

Re: DS: x=? [#permalink]

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New post 11 Dec 2008, 18:48
Agree with LiveStronger but with slight change

stmt2: You get x = 4 or -5 - In Suff
stmt1 : In Suff

sub x= 4 we get b = -8
and x = -5 we get b = 41/5

so b +ve only when x = -5.

Kudos [?]: 48 [0], given: 0

Re: DS: x=?   [#permalink] 11 Dec 2008, 18:48
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x^2 + bx + 16 = 0, b is constant. What is the value of x?

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