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# X = 2*(P/ Q)^n+1. Find X if P, Q and n are positive integers.

Author Message
Manager
Joined: 13 May 2017
Posts: 104
Location: Finland
Concentration: Accounting, Entrepreneurship
GMAT 1: 530 Q42 V22
GPA: 3.14
WE: Account Management (Entertainment and Sports)
X = 2*(P/ Q)^n+1. Find X if P, Q and n are positive integers.  [#permalink]

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10 Oct 2018, 04:30
2
00:00

Difficulty:

65% (hard)

Question Stats:

44% (02:08) correct 56% (01:35) wrong based on 25 sessions

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$$X = 2*(\frac{P}{Q})$$$$^(^n^+^1^)$$. Find X if P, Q and n are positive integers.

(1) Both P and Q have only 3 factors
(2) $$\frac{P^(^n^-^1^)}{Q^(^2^n^-^1^)}= \frac{49}{64}$$
Intern
Joined: 30 Sep 2018
Posts: 2
Re: X = 2*(P/ Q)^n+1. Find X if P, Q and n are positive integers.  [#permalink]

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10 Oct 2018, 06:29
a) not sufficient
b) because both P and Q have to be integers P can be either 7 or 49. Let's suppose P is 7, n = 3, however doesn't exist any Q^5=64.
If P =49, n=2 and Q^3=64 is satisfied by 4.
As far as I see, the answer should be B
Re: X = 2*(P/ Q)^n+1. Find X if P, Q and n are positive integers.   [#permalink] 10 Oct 2018, 06:29
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