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while chkn the possible values in st 2..

what if x is 0..

the eqn becomes 4 < 4 ?
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bindrakaran001
while chkn the possible values in st 2..

what if x is 0..

the eqn becomes 4 < 4 ?

under statement 2 |x-2|+|x+2| always equals 4.
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For x < -2, the inequality gives the result as x > -2.....not possible.
For -2 < x < 2, the inequality gives the result as 4 < 4....not possible.
Forx > 2, the iniequality gives the result as x < 2....not possible.

Thus, for any value of x, the given inequality is not possible and hence, answer will be D.
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bindrakaran001
while chkn the possible values in st 2..

what if x is 0..

the eqn becomes 4 < 4 ?

Precisely. The question doesnt mention ¦x-2¦+¦x+2¦<=4?, its only mentions ¦x-2¦+¦x+2¦<4?
So, why D? you dont have a definitive answer.



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