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Sub 505 (Easy)|   Algebra|            
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HKD1710
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x^2 - (x/2)^2 = 14 Dec 2018, 10:14
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92% (00:32) correct 8% (01:07) wrong based on 1056 sessions

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\(x^2 - (\frac{x}{2})^2 =\)

(A) \(x^2 - x\)

(B) \(\frac{x^2}{4}\)

(C) \(\frac{x^2}{2}\)

(D) \(\frac{3x^2}{4}\)

(E) \(\frac{3x^2}{2}\)
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D
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x^2 - (x/2)^2 = 14 Dec 2018, 10:23
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HKD1710
\(x^2 - (\frac{x}{2})^2\) =

(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)

 
Show more

we can apply \(a^2 - b^2 = (a+b) (a-b)\)

\(x^2 - (x/2)^2\)

(x + x/2) ( x - x/2)

(\(\frac{2x + x}{2}\)) (\(\frac{2x - x}{2}\))

\(\frac{3x *x}{4}\)

\(\frac{3x^2}{4}\)

The best answer is D.­
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x^2 - (x/2)^2 = 22 Jun 2019, 04:05
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KSBGC

HKD1710
\(x^2 - (\frac{x}{2})^2\) =

(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)

 

we can apply \(a^2 - b^2 = (a+b) (a-b)\)

\(x^2 - (x/2)^2\)

(x + x/2) ( x - x/2)

(\(\frac{2x + x}{2}\)) (\(\frac{2x - x}{2}\))

\(\frac{3x *x}{4}\)

\(\frac{3x^2}{4}\)

The best answer is D.
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Hey, is solving mathematically right too ?

As in

X^2 - (X/2)^2
X^2 - X^2/4
(4X^2- X^2)/4
3x^2/4..­
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x^2 - (x/2)^2 = 24 Jun 2019, 13:51
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We can also plug a value, it's as quick and efficient;

plug 1 to get 1^2-(1/2)^2=1-0.25=0.75-->3/4 so 3x^2/4 with x=1 is 3/4: Answer D.
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x^2 - (x/2)^2 = 17 Nov 2021, 08:22
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HKD1710
\(x^2 - (\frac{x}{2})^2\) =

(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)

 
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\(x^2 - (\frac{x}{2})^2\)

=\(x^2 - \frac{x^2}{4}\)

\(= \frac{3x^2}{4}\), Answer will be (D)­
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x^2 - (x/2)^2 = 05 Sep 2024, 08:10
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