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GMAT Club Legend  V
Joined: 11 Sep 2015
Posts: 4959
GMAT 1: 770 Q49 V46
x and y are positive integers. When 16x is divided by y,  [#permalink]

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Top Contributor
11 00:00

Difficulty:   75% (hard)

Question Stats: 60% (02:38) correct 40% (02:40) wrong based on 210 sessions

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x and y are positive integers. When 16x is divided by y, the quotient is x, and the remainder is 4. What is the sum of all possible y-values?

A) 7
B) 12
C) 19
D) 26
E) 41

*Kudos for all correct solutions

_________________

Originally posted by BrentGMATPrepNow on 27 Feb 2017, 08:34.
Last edited by BrentGMATPrepNow on 27 Feb 2017, 09:21, edited 1 time in total.
Director  V
Joined: 05 Mar 2015
Posts: 938
Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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GMATPrepNow wrote:
x and y are positive integers. When 16x is divided by y, the quotient is x, and the remainder is 4. What is the sum of all possible y-values?

A) 7
B) 12
C) 19
D) 26
E) 39

*Kudos for all correct solutions

16x = yx+4
y=(16x-4)/x

if x=1 then y =12
if x= 2 then y= 14
if x=3 y is no longer integer
if x=4 then y = 15

upto here y = 12+14+15 = 41...
but i m not finding any such option.....

can any one explain!!!!!

thanks
GMAT Club Legend  V
Joined: 11 Sep 2015
Posts: 4959
GMAT 1: 770 Q49 V46
Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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Top Contributor
Yeesh, I added those values several times and got 39 each time.
I've changed answer choice E to the correct value.

Cheers and thanks,
Brent
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Joined: 13 Oct 2016
Posts: 352
GPA: 3.98
Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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1
1
GMATPrepNow wrote:
x and y are positive integers. When 16x is divided by y, the quotient is x, and the remainder is 4. What is the sum of all possible y-values?

A) 7
B) 12
C) 19
D) 26
E) 39

*Kudos for all correct solutions

Hi

It seems I've missed something.

16x = yx + 4

16x - yx = 4

x(16 - y) = 4 (1*4), (2*2) and (4*1). I'm discarding negativ values because our x an y are >0.

x=1, 16 - y = 4 ---> y=12, check: 16*1 = 12*1 + 4

x = 2, 16 - y = 2 -----> y = 14, check: 32 = 14*2 + 4

x = 4, 16 - y = 1 -------> y=15, chek: 64 = 15*4 + 4

4<y<16

12+14+15 = 41

I'm not getting 39. Please correct me.
GMAT Club Legend  V
Joined: 11 Sep 2015
Posts: 4959
GMAT 1: 770 Q49 V46
Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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Top Contributor
You're correct, vitaliyGMAT

It seems I have not yet mastered addition. Cheers,
Brent
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Senior Manager  B
Joined: 13 Oct 2016
Posts: 352
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Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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GMATPrepNow wrote:
You're correct, vitaliyGMAT

It seems I have not yet mastered addition. Cheers,
Brent

Thanks

Your questions are really good! Please keep posting, just don't hurry next time GMAT Club Legend  V
Joined: 11 Sep 2015
Posts: 4959
GMAT 1: 770 Q49 V46
Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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1
Top Contributor
3
GMATPrepNow wrote:
x and y are positive integers. When 16x is divided by y, the quotient is x, and the remainder is 4. What is the sum of all possible y-values?

A) 7
B) 12
C) 19
D) 26
E) 41

There's a nice rule that say, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3

------NOW ONTO THE QUESTION------------------------------

When 16x is divided by y, the quotient is x, and the remainder is 4.
Applying the above rule, we can write: 16x = (y)(x) + 4
Subtract xy from both sides: 16x - xy = 4
Factor: x(16 - y) = 4

Since x and (16 - y) are both positive integers, there are 3 possible solutions:
#1: x = 1 and (16 - y) = 4, in which case y = 12
#2: x = 2 and (16 - y) = 2, in which case y = 14
#3: x = 4 and (16 - y) = 1, in which case y = 15

What is the sum of all possible y-values?
SUM = 12 + 14 + 15
= 41

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Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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2
Great question! I solved it a very similar way to you all.
(16x)/y = x + 4
--> 16x = xy + 4 --> y = (16x - 4)/x ---> y = 16 - 4/x.

We know from the prompt that Y is an integer, therefore, the only values of X that will make Y and integer is 0, 1, 2, 4. However, the prompt says that X & Y are positive integers. Therefore we can't use 0. So plugging in the values of 1, 2, and 4 into the equation, you're left with 15 + 14 + 12 = 41.
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Joined: 09 Oct 2017
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Location: India
Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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X and y are positiv integers
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Posts: 15418
Re: x and y are positive integers. When 16x is divided by y,  [#permalink]

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_________________ Re: x and y are positive integers. When 16x is divided by y,   [#permalink] 09 Jun 2020, 12:15

# x and y are positive integers. When 16x is divided by y,   