amanvermagmat wrote:
X and Y are two positive numbers. Is X > Y ?
(1) (X+Y)/2 > Y
(2) X is Z% less than the sum (X+Y), where Z is a positive number and Z < 40.
If \(X=Y\) then \(X=Y=\frac{(X+Y)}{2}=(X+Y)∗(1−\frac{50}{100})\)
(1) \(\frac{(X+Y)}{2}>Y\) --> X < Y -> Sufficient.
(2) \(X= (X+Y)*(1-\frac{Z}{100})\).
Since \(Z<40\), \((X+Y)*(1-\frac{Z}{100}) > (X+Y)∗(1−\frac{50}{100})\) --> \(X>(X+Y)∗(1−\frac{50}{100})\), thus X > Y -> Sufficient.
Answer D.
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68% (01:32) correct 
