Hi
Bunuel,
Although I got the correct answer A, I am still confused with the explaination.
Since X and Y are placed on the diametrically opposite point, and they run in opposite direction, then how will they require half the track length distance for meeting first time?
Assume a clock face. X at 12 and Y at 6. so X starts moving towards left (anti clockwise) and Y starts also moving towards left (clockwise), then they meet somewhere between 7 to 11 in clock face. Suppose their speed is same then they meet at 9. But thats a quarter of the track length (less than half), and now they keep travelling for half the track length and meet for the 2nd time at 3 in clock face. The explaination remains intact even if X and Y have unequal speeds.
So, if they travel suppose distance d for meeting first time, then they have to travel a additonal distance of 2d (total 3d) for meeting 2nd time and so the time is 3*40s =120s.
Please rectify me if I am wrong.
Bunuel
Starting from diametrically opposite points on a circular track and running in opposite directions, X and Y will meet each other after together covering half the track's length. Following this first meeting, they continue to run and will meet each other again after together covering an additional full track length. Consequently, by the time of their second meeting, they would have covered 0.5 + 1 = 1.5 track lengths in total.
Statement (1) says that their initial meeting takes place 40 seconds after they start. This implies that it takes them 40 seconds to collectively cover half the track length. Hence, to cover 1.5 track lengths, they would need 40*3 = 120 seconds.
On the other hand, Statement (2) is irrelevant because it fails to provide specific details about their individual speeds or the actual time each of them spent running.
Answer A.
Hope it's clear.