x^n + x^n + x^n + x^n = x^(n + 1). What is the value of n?

Question

x^n + x^n + x^n = x^{n+1}

What is the value of n?

(1)  x^n = 9\sqrt{3}

(2)  x = 3

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chetan2u · Answer

x^n + x^n + x^n = x^{n+1}........3*x^n=x^n*x.........x^n(3-x)=0 
Thus either x^n=0 or x=3

What is the value of n?

(1)  x^n = 9\sqrt{3} 
So x=3as  x^n
eq{0} 
So  3^n=9\sqrt{3} ..
We can find n from it. 
  3^n=9\sqrt{3}=3^{5/2} ..n=5/2

(2)  x = 3 
Insufficient

A

The question should be  x^n+x^n+x^n=x^{n+1}

nick1816 · Answer

You are absolutely correct.

At x=3, x^n(4-x)=0 can never be 0 for real values of n.

Question is flawed imo.

Its_me_aka_ak · Answer

why is st 2 insufficient. i believe n would1 acccording it it

Bunuel · Answer

If x = 3, then we get:
 
 3^n + 3^n + 3^n = 3^{n+1}

3*3^n = 3^{n+1}

3^{n+1} = 3^{n+1} 
 
The above is true for any value of n. Hence, (2) is not sufficient.

Hope it's clear.

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