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# x2 + bx + 72 = 0 has two distinct integer roots; how many values are p

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Senior Manager
Joined: 29 Nov 2018
Posts: 280
Concentration: Marketing, Strategy
x2 + bx + 72 = 0 has two distinct integer roots; how many values are p  [#permalink]

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30 Dec 2018, 14:57
2
3
00:00

Difficulty:

55% (hard)

Question Stats:

38% (01:55) correct 62% (01:11) wrong based on 13 sessions

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x^2 + bx + 72 = 0 has two distinct integer roots; how many values are possible for 'b'?

A. 3
B. 12
C. 6
D. 24
E. 8

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Math Expert
Joined: 02 Sep 2009
Posts: 58434
Re: x2 + bx + 72 = 0 has two distinct integer roots; how many values are p  [#permalink]

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31 Dec 2018, 00:48
cfc198 wrote:
x^2 + bx + 72 = 0 has two distinct integer roots; how many values are possible for 'b'?

A. 3
B. 12
C. 6
D. 24
E. 8

If you liked the question, please do hit the kudos button

Discussed here: https://gmatclub.com/forum/x-2-bx-72-0- ... 14644.html
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Re: x2 + bx + 72 = 0 has two distinct integer roots; how many values are p  [#permalink]

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31 Dec 2018, 04:19
cfc198 wrote:
x^2 + bx + 72 = 0 has two distinct integer roots; how many values are possible for 'b'?

A. 3
B. 12
C. 6
D. 24
E. 8

If you liked the question, please do hit the kudos button

[quote="cfc198"]x^2 + bx + 72 = 0

72= 2^3 * 3^2 = (3+1)*(2+1) = 4*3 =12
IMO B
Re: x2 + bx + 72 = 0 has two distinct integer roots; how many values are p   [#permalink] 31 Dec 2018, 04:19
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