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# y is not zero, is (2^x/y)^x<1? 1). x>y 2). y< 0

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Manager
Joined: 04 Sep 2008
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Location: Kolkata
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y is not zero, is (2^x/y)^x<1? 1). x>y 2). y< 0  [#permalink]

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27 Oct 2008, 05:31
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y is not zero, is (2^x/y)^xy
2). y< 0

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rampuria

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Joined: 28 Jul 2004
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27 Oct 2008, 07:41
(2^x/y)^x = (2^x)^x/(y)^x

from (1) x > y --> x^x > y^x --> 2^x^x > y^x --> (2^x/y)^x > 1 and hence Sufficient

(2) does not talk about x ..Not Suffcient

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kris

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Joined: 28 Dec 2004
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27 Oct 2008, 07:55
i would go with B..

if y is negative then we have a fraction..
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27 Oct 2008, 09:36
rampuria wrote:
y is not zero, is (2^x/y)^x<1?
1). x>y
2). y< 0

agree with B.

(2^x/y)^x = 2^(x^2/y)

1) x > y : not sure about y, which could be -ve or +ve. Either is suff but we need to know y whether it is -ve or +ve.

2) y< 0 : y is -ve. suff. the power of 2 becomes -ve, yeilding a +vwe fraction value.
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Posts: 135
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth

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27 Oct 2008, 13:25
GMAT TIGER wrote:
rampuria wrote:
y is not zero, is (2^x/y)^x<1?
1). x>y
2). y< 0

agree with B.

(2^x/y)^x = 2^(x^2/y)

1) x > y : not sure about y, which could be -ve or +ve. Either is suff but we need to know y whether it is -ve or +ve.

2) y< 0 : y is -ve. suff. the power of 2 becomes -ve, yeilding a +vwe fraction value.

Oh.. I got the question wrong. I read it as 2^x is divided by y and complete thing raised ti power x. It looks like the stem is 2 raised to the power x/y and complete thing raised to power x.
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kris

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Joined: 05 Jul 2008
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27 Oct 2008, 14:08
krishan wrote:
GMAT TIGER wrote:
rampuria wrote:
y is not zero, is (2^x/y)^xy
2). y y : not sure about y, which could be -ve or +ve. Either is suff but we need to know y whether it is -ve or +ve.

2) y< 0 : y is -ve. suff. the power of 2 becomes -ve, yeilding a +vwe fraction value.

Oh.. I got the question wrong. I read it as 2^x is divided by y and complete thing raised ti power x. It looks like the stem is 2 raised to the power x/y and complete thing raised to power x.

Yep! I was wondering whether the Q is

$$( 2 ^ (x/y) ) ^ x or ( ( 2 ^ x) / y ) ^ x$$

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Re: DS &nbs [#permalink] 27 Oct 2008, 14:08
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