Hi 0akshay0,
While solving age problems such as these there are three things that will help you solve such questions quickly and without any tedious working.
1. Limit the number of variables you choose to solve the question (Choose one or at most 2 variables)
2. Always put in the data given in age problems in a table with past, present and future ages as the rows and the people (A, B and C) as columns
3. Always read the question in parts and translate the statements into mathematical equations
Let the present age of 'B' be 'x'. "You were a quarter of my age when I was twice of your present age", said A to B.
So in the past A's age was
2x and B's age in the past was
x/2. Let these past ages be
'y' years ago.
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The present age of 'A' will now be '
2x + y' and the present age of 'B' which is '
x' will be '
x/2 + y'. So
y = x/2.
"5 years from now, our ages will add up to 45" ------> 2x + y + 5 + x + 5 = 45 ------> 2x + x/2 + 5 + x + 5 = 45. Simplifying we get
3x + x/2 = 35 ----->
x = 10. So B's present age is 10. 5 years ago B's age was 5 and A's age was 20. So when B was born, A's age was
20 - 5 = 15.
OA : B