My approach was slightly different. For (1) and (2) together:
The correct change could have consisted of exactly 2 coins, each with a value of 1, 5, 10 or 25. So out of all possible combinations we can make, they'll be only of 2 types: either the sum will be a multiple of 5 or not a multiple of 5. For example, they can be (25,25) or (10,5) or (10,10) (sum is a multiple of 5) or (1,5), (1,10) (non-multiple of 5). We leave this here for now.
We also know that out of the 4 actual coins, one of them is 1. So for the remaining 3, we can see that there is no possible combination such that the final sum would be a multiple of 5. For example, (1,5,5,10), (1,1,10,25), (1,1,1,10). There's no way we can have a multiple of 5 as the sum.
Back to the previous finding: Since the sum is not a multiple of 5, therefore one of the coins out of the two has to be 1 (or else the sum would be a multiple of 5).
After we find this, we can make all possible combinations: (1,1) = 2, (1,5) = 6, (1,10) = 11, (1,25) = 26
Out of these four, only one is possible, i.e. (1,25) -> (1,5,10,10)
Sorry for the poor formatting.