| Giver | Post | Date |
| alitharani95 | A hotel has 80 rooms and charges the same amount per night for each | 30-Aug-2026 |
| officiisnobis | A hotel has 80 rooms and charges the same amount per night for each | 29-Aug-2026 |
| anjichowdhury | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 28-Aug-2026 |
| UltraCar | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 26-Aug-2026 |
| UltraCar | Consider all positive integers a, b, and c such that | 26-Aug-2026 |
| JeanneJu1013 | Forests in Thailand can be divided into two major | 25-Aug-2026 |
| WildMug | A hotel has 80 rooms and charges the same amount per night for each | 25-Aug-2026 |
| Dakshinesh | Consider all positive integers a, b, and c such that | 19-Aug-2026 |
| dolorumomnis | A hotel has 80 rooms and charges the same amount per night for each | 19-Aug-2026 |
| fahad99 | Consider all positive integers a, b, and c such that | 16-Aug-2026 |
| TrueCode | A hotel has 80 rooms and charges the same amount per night for each | 11-Aug-2026 |
| WildMug | Consider all positive integers a, b, and c such that | 03-Aug-2026 |
| Amity007 | Consider all positive integers a, b, and c such that | 27-Jul-2026 |
| ssb1989 | Consider all positive integers a, b, and c such that | 18-Jul-2026 |
| arunbhati | A hotel has 80 rooms and charges the same amount per night for each | 18-Jul-2026 |
| Yash0024 | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 16-Jul-2026 |
| RoyalGoat | Consider all positive integers a, b, and c such that | 11-Jul-2026 |
| owenchung24 | Consider all positive integers a, b, and c such that | 25-Jun-2026 |
| vrundaparikh05 | Forests in Thailand can be divided into two major | 24-Jun-2026 |
| JeanneJu1013 | A hotel has 80 rooms and charges the same amount per night for each | 22-Jun-2026 |
| lvsgndrv | Consider all positive integers a, b, and c such that | 16-Jun-2026 |
| HT2025 | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 15-Jun-2026 |
| cumquehic | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 15-Jun-2026 |
| irene108 | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 13-Jun-2026 |
| Dhruv06 | A hotel has 80 rooms and charges the same amount per night for each | 31-May-2026 |
| surajs838 | Consider all positive integers a, b, and c such that | 31-May-2026 |
| RahulBD | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 28-May-2026 |
| ssb1989 | If x 1, then (x^n - 1)/(x - 1) = x^{n - 1} + x^{n - 2} + ... + x^2 | 25-May-2026 |
| SSS19 | A hotel has 80 rooms and charges the same amount per night for each | 24-May-2026 |
| surajs838 | A hotel has 80 rooms and charges the same amount per night for each | 21-May-2026 |
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