rsrighosh wrote:
I have a serious problem in dealing with such kind of problems. Can anybody please help me out how can I attack such problems. Any key strategies?
For example:-
In this problem this was my approach which of course did not match with the options
Scenario given
5 _ _ _ _ _( _ _
H)
(_ _ H) = 60
Hence my approach was to make H highest was
5 5 5 5 10 10 20 20 20I took this approach because in other such questions, to get the highest of the list of numbers, if i replace the rest with the least numbers, it works.
But of course i couldnt find it out this way.
I saw the other discussons and realised this is the correct set of numbers
5 7 7 7 7 7 7 7 7 46which was found out by keeping least number 5 one time.. and H being the highest equations were
5 + 7x + H = 100
2x + H = 60
H = 46, x=7
I need help desperately
Bunuel bb VeritasKarishma egmat chetan2uThis is a type of max-min question. Here are some posts on such questions:
https://www.veritasprep.com/blog/2014/0 ... -the-gmat/https://www.veritasprep.com/blog/2014/0 ... base-case/https://www.veritasprep.com/blog/2014/0 ... -extremes/In this question, the first thing I do is give 5 to each of the 9 people. 45 are gone and 55 are left.
5, 5, 5, ... 5, 5, 5
I need to maximise Greatest/Least so Greatest must be as large as possible and least must be as small as possible (5).
The largest 3 must have total 60. They already have 15 so another 45 need to be given to them. We are left with 10 beans. These 10 must be given to the other 6 people. Since I want the least to be smallest, I give it no beans and just give 2 each to the other 5 people.
5, 7, 7, 7, 7, 7, ??, ??, ??
The last 3 must be at least 7 and the greatest must be as big as possible. Let's give 7 each to two of them and 46 to the greatest one
5, 7, 7, 7, 7, 7, 7, 7, 46
Answer (B)
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Karishma
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