Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..- Jun 10
10:00 AM PDT
-11:00 AM PDT
Scoring 715 on the GMAT Focus Edition requires more than just learning formulas, memorizing concepts, or solving hundreds of questions. In this episode, Nishant shares how he improved his GMAT preparation by focusing on application of concepts, and more. 
Jun 1111:00 AM EDT
-01:00 PM EDT
TTP GMAT OnDemand gives serious students 400+ hours of expert video instruction, the full TTP course, AI support, weekly office hours, and a 715+ score guarantee—all built for elite GMAT score improvement.
Jun 2207:30 PM EDT
-09:30 PM EDT
Master the GMAT with expert live instruction, a personalized study plan, and real-time support. Includes 40 hours of online classes plus 6 months of access to the TTP GMAT OnDemand video course. Class date: Mon/Wed June 22, 2026 →August 26, 2026
18 Dec 2025, 11:10
Kudos
Bookmarks
Bunuel
Let x = day 1 rate, y= day 1 hours, and z=day 2 hours.
\(y+z=14\)
Total work done:
\(xy+(x-8)z=240\)
\(xy+(x-8)(14-y)=240\)
Simplifies to:
\(7x-4y=181\)
Now we need to find rates from the options that, when subbed in, make RHS divisible by -4.
I. \(y=\frac{118}{-4}\), not an integer, incorrect.
II. \(y=\frac{142}{-4}\), not an integer, incorrect.
III. \(y=\frac{48}{4}\), integer, correct.
Therefore answer is C.
18 Dec 2025, 11:21
Kudos
Bookmarks
Answer B
Let x be rate on 2nd day, and x=8 the rate of work on 1st day
Let h1 be hours worked on first day. h2 is hours worked on 2nd day.
First day work is h1 x (x+8) + 2nd day h2 x (x) H2 + h1 = 14 h2 = 14 - h1
Total cleared 240 = h1 (x +8) + h2 x (x) = h1(x +8) + 14 - h1 (x)
240 = h1x + 8 h1 + 14x - h1(x)
240 = 8 h1 + 14x
h1 = 240 - 14x / 8
for 9 240 - 126 / 8 = 14.25 greater than 14 hours incorrect
for 14 240 - 14(14) / 8 = 5.5 hours works
for 19 240 - 14(19) / 8 = 240 - 266 / 8 negative number incorrect
Let x be rate on 2nd day, and x=8 the rate of work on 1st day
Let h1 be hours worked on first day. h2 is hours worked on 2nd day.
First day work is h1 x (x+8) + 2nd day h2 x (x) H2 + h1 = 14 h2 = 14 - h1
Total cleared 240 = h1 (x +8) + h2 x (x) = h1(x +8) + 14 - h1 (x)
240 = h1x + 8 h1 + 14x - h1(x)
240 = 8 h1 + 14x
h1 = 240 - 14x / 8
for 9 240 - 126 / 8 = 14.25 greater than 14 hours incorrect
for 14 240 - 14(14) / 8 = 5.5 hours works
for 19 240 - 14(19) / 8 = 240 - 266 / 8 negative number incorrect
Bunuel
18 Dec 2025, 11:42
Kudos
Bookmarks
Bunuel
A farmer is working for two days. D1 and D2 respectively.
Given that the rate of day 2 is 8 less than the rate of day 1.
Since the answer is given as rate for day 2, we can assume rate for day 2 as a.
Let the rates of the farmer on day 1 and day be : (a+8) and a respectively.
Given, the total time is 14 hours.
If the time taken on Day 1 is t hours, then time taken for Day 2 = (14-t) hours.
In these 2 days, the total work done is 240.
(a+8)*t + a * (14-t) = 240
at + 8t + 14a - at = 240
8t + 14a = 240
4t + 7a = 120
Lets look into the options,
I) a = 9, then 120 - 7a = 4t , solving we get t = 14.xx
Since t >= 14 , a=9 cannot be the answer.
II) a = 14, then 120 -7a = 4t , solving t = 5.5
a =14 can be an answer, as t =<14.
III) a=19, 120 - 7*(19) = 4t , solving we get t = negative.
Not possible.
Option B (II)
