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16 Dec 2024, 10:24
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To ensure Sarah gets at least one lemon flavored candy, we consider all the candies in the jar. There are 18 orange flavored candies and 24 strawberry flavored candies. To guarantee she picks at least one lemon candy, we need to consider all the orange and strawberry candies first:
18 (orange)+24 (strawberry)+1 (lemon)=43 candies
18 (orange)+24 (strawberry)+1 (lemon)=43 candies
Therefore, Sarah must pick at least 43 candies to ensure she gets at least one lemon flavored candy.
For the strawberry flavored candies, we do a similar calculation. There are 18 lemon flavored candies and 18 orange flavored candies. To be sure she picks at least one strawberry flavored candy, we need to consider all the orange and lemon candies first:
18(orange)+18 (lemon)+1 (strawberry)=37 candies
18 (orange)+18 (lemon)+1 (strawberry)=37 candies
Therefore, Sarah must pick at least 37 candies to ensure she gets at least one strawberry flavored candy.
18 (orange)+24 (strawberry)+1 (lemon)=43 candies
18 (orange)+24 (strawberry)+1 (lemon)=43 candies
Therefore, Sarah must pick at least 43 candies to ensure she gets at least one lemon flavored candy.
For the strawberry flavored candies, we do a similar calculation. There are 18 lemon flavored candies and 18 orange flavored candies. To be sure she picks at least one strawberry flavored candy, we need to consider all the orange and lemon candies first:
18(orange)+18 (lemon)+1 (strawberry)=37 candies
18 (orange)+18 (lemon)+1 (strawberry)=37 candies
Therefore, Sarah must pick at least 37 candies to ensure she gets at least one strawberry flavored candy.
16 Dec 2024, 10:29
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S= 24, L=18, O=18. Therefore min. candies for lemon= 24+18+1 (let's say worst case when I pick up first 24 candies I get 'S' type, further, lets say for the next 18 picks I get all the 'O' type, therefore If i pick even 1 more after this i'll get an 'L' type for sure). Therefore, candies for strawb.= 18+18+1
16 Dec 2024, 10:38
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well In computer science these Qs are knows as based on Pigeonhole principle {just making you revise from discrete Maths}.
we go by worst case scenario here:
A candy jar contains 60 candies:
let us say if we are picking Lemon candy and it is not our lucky day we might get 24 Straberry candy first which we do not want and since we are still not lucky we might get another 18 orange candy not which sums up to be 42 now the next candy we pick is definately of Lemon flavour.
we can follow the same unlucky procedure for strawberry candies,
that is 18 orange first and then 18 lemon which is 36 now the next candy you know must be Strawberry which is 37th in the no
hence 43 and 37.
we go by worst case scenario here:
A candy jar contains 60 candies:
let us say if we are picking Lemon candy and it is not our lucky day we might get 24 Straberry candy first which we do not want and since we are still not lucky we might get another 18 orange candy not which sums up to be 42 now the next candy we pick is definately of Lemon flavour.
we can follow the same unlucky procedure for strawberry candies,
that is 18 orange first and then 18 lemon which is 36 now the next candy you know must be Strawberry which is 37th in the no
hence 43 and 37.
