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17 Dec 2024, 06:40
Kudos
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A candy jar contains 60 candies: 24 identical strawberry flavored, 18 identical lemon flavored, and 18 identical orange flavored.
To ensure getting atleast one lemon flavoured candy, there should be no strawberry or orange flavoured left in the jar, so 42 picks used there, and the next one for the lemon flavored
So 43
Similarly to ensure getting atleast one strawberry flavoured candy, there should be no lemon or orange flavoured left in the jar, so 36 picks used there, and the next one for the lemon flavored
So 37
To ensure getting atleast one lemon flavoured candy, there should be no strawberry or orange flavoured left in the jar, so 42 picks used there, and the next one for the lemon flavored
So 43
Similarly to ensure getting atleast one strawberry flavoured candy, there should be no lemon or orange flavoured left in the jar, so 36 picks used there, and the next one for the lemon flavored
So 37
17 Dec 2024, 06:58
Kudos
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To ensure 1 lemon candy, we have to consider the worst case scenario, since we have to ENSURE.
The worst case scenario is that, that we select all the strawberry and orange flavoured first, and then get one lemon flavoured.
24 + 18 = 42.
next selection will ENSURE our 1 lemon flavoured. Hence, 43.
To ensure 1 strawberyy candy, we have to consider the worst case scenario, since we have to ENSURE.
The worst case scenario is that, that we select all the lemon and orange flavoured first, and then get one strawberry flavoured.
18 + 18 = 36.
next selection will ENSURE our 1 lemon flavoured. Hence, 37.
The worst case scenario is that, that we select all the strawberry and orange flavoured first, and then get one lemon flavoured.
24 + 18 = 42.
next selection will ENSURE our 1 lemon flavoured. Hence, 43.
To ensure 1 strawberyy candy, we have to consider the worst case scenario, since we have to ENSURE.
The worst case scenario is that, that we select all the lemon and orange flavoured first, and then get one strawberry flavoured.
18 + 18 = 36.
next selection will ENSURE our 1 lemon flavoured. Hence, 37.
Bunuel
17 Dec 2024, 07:47
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Bunuel
This question tests on a concept called pigeon hole principle. To get Lemon.
He need to draw 24(Staw..)+18(Oran..)+1(Lem..) Think of the worst-case scenario. Hence Min to assure at least one lemon is 43.
Similarly for Strawberry. 18+18+1=37.
43,37 are the answers.
