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19 Dec 2024, 03:28
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Hi Everyone 
Straightforward.
1 digit: 1-9 = 9 numbers
2 digits: 10-99 = 90*2= 180 numbers
We need to find the 341th so: 341-180-9=152
152th from 99.
[152][/3]=[150+2][/3]= 50 +2/3
50 numbers => resulting in number 149. (100-109 = 10 numbers, and so on)
Thus we have the number 150. 2 digits after resulting in the number 5.
5 is our answer.
Straightforward.
1 digit: 1-9 = 9 numbers
2 digits: 10-99 = 90*2= 180 numbers
We need to find the 341th so: 341-180-9=152
152th from 99.
[152][/3]=[150+2][/3]= 50 +2/3
50 numbers => resulting in number 149. (100-109 = 10 numbers, and so on)
Thus we have the number 150. 2 digits after resulting in the number 5.
5 is our answer.
19 Dec 2024, 03:58
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Bunuel
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If k is the number formed by writing the integers from 1 to 999 sequentially (123456789101112...998999), what is the 341st digit in k?
A. 0
B. 1
C. 4
D. 5
E. 9
If k is the number formed by writing the integers from 1 to 999 sequentially (123456789101112...998999), what is the 341st digit in k?
A. 0
B. 1
C. 4
D. 5
E. 9
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We've used 189 digits for single-digit and two-digit numbers.
- We have 189 digits for single-digit and two-digit numbers.
- aHave 50 * 3 = 150 digits from three-digit numbers, up to 149.
- 341st digit will be the second digit of the 51 three-digit number, 5.
19 Dec 2024, 04:22
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I did it mechanically.
12345678910- here 0 is the 11th digit.
11121314151617181920- here 0 is 31st digit.
so now there is a pattern till we are dealing with the 2 digit numbers we will add 20 in the previous digit we have find 0. ex- now to find the next 0 we will add 20 to 31st digit- 51st digit and so on.
so we will get series here- 31,51,71,91,.....181. here 181 st digit represents the tens 0 in number 100.
so now since we will deal with 3 digit numbers we will start adding 30.
ex- add 31 since we have to take hundread digit 0 into consideration as well.- 212 digit will be zero in 110.
now, keeping on adding 30- 252,282,312,342.
here 342nd digit is the zero in 150 so 341st digit is 5
12345678910- here 0 is the 11th digit.
11121314151617181920- here 0 is 31st digit.
so now there is a pattern till we are dealing with the 2 digit numbers we will add 20 in the previous digit we have find 0. ex- now to find the next 0 we will add 20 to 31st digit- 51st digit and so on.
so we will get series here- 31,51,71,91,.....181. here 181 st digit represents the tens 0 in number 100.
so now since we will deal with 3 digit numbers we will start adding 30.
ex- add 31 since we have to take hundread digit 0 into consideration as well.- 212 digit will be zero in 110.
now, keeping on adding 30- 252,282,312,342.
here 342nd digit is the zero in 150 so 341st digit is 5
