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3 machines working together for 10 hours = 1/2 of the task done.
(6/300 + 5/300 + 4/300)*10 = 1/2

Now if T is total time worked to complete task, then B and C work together for t - 15 hours and the remaining last 15 hours must be completed by C alone.

Which translates into B&C + C = 1/2 of the job.

(t-15)9/300 + 15*(1/75) = 1/2

solving for T = 25 hours Answer (A)
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IMO C



To determine the total hours required to finish the task, we need to calculate the contributions of each machine and the total work done.
  1. Calculate the work rates of each machine:

    • Machine A's rate: 1/50 of the task per hour.
    • Machine B's rate: 1/60 of the task per hour.
    • Machine C's rate: 1/75 of the task per hour.
  2. Calculate the work done by each machine:

    • Machine A worked for 10 hours.
    • Machine B worked until 15 hours before the task was completed.
    • Machine C worked the entire time.
Let TT be the total time required to complete the task.
  1. Work done by Machine A:
    Work done by A=10×1/50=10/50=1/5
  2. Work done by Machine B: Machine B stopped 15 hours before the task was completed, so it worked for T−15hours.
    Work done by B=(T−15)×1/60
  3. Work done by Machine C: Machine C worked the entire time T.
    Work done by C=T×1/75
  4. Total work done: The sum of the work done by all machines should equal 1 (the entire task).
    1/5+(T−15)×1/60+T×1/75=1
  5. Combine and solve the equation:
    1/5+T−15/60+T/75
    To combine the fractions, find a common denominator. The least common multiple of 5, 60, and 75 is 300.
    Convert each term to have a denominator of 300:

    15=60300,160=5300,175=430051=30060,601=3005,751=3004
    T=35
Therefore, the total hours required to finish the task is 35.
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Total hours is T

B+C work for T-15 hours
C works alone for 15 hours
A+B+C work for 10 hours now

Combining rates we get that all three combined accomplish half the work so B and C must finish it.

B+C*(t-15) + C*15 = 1/2 of the work and inserting here the combined rates we get T = 25 (a)

t-15 = 10, which is the number of hours worked by B and C alone
and the first 10 hours is done by the 3 of them.
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