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Manasvi1
If \(\sqrt{13 - a√10} = \sqrt{8} + \sqrt{5}\), then find the value of a.

A) +5
B) -6
C) +6
D) -4
E) +7

Solution:

Squaring both sides, we have:

13 - a√10 = 8 + 5 + 2√40

-a√10 = 2√40

-a = 2√4

-a = 4

a = -4

Answer: D

Would you please explain this part?

13 - a√10 = 8 + 5 + 2√40

Thanks. :)
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Manasvi1
If \(\sqrt{13 - a√10} = \sqrt{8} + \sqrt{5}\), then find the value of a.

A) +5
B) -6
C) +6
D) -4
E) +7

Square both sides..
\((\sqrt{13 - a√10})^2=(\sqrt{8} + \sqrt{5})^2\),

\(13 - a√10= \sqrt{8}^2 + \sqrt{5}^2+2*\sqrt{8}*\sqrt{5}=8+5+2\sqrt{40}=13+2\sqrt{40}\),

\(13-a\sqrt{10}=13+2\sqrt{40}=13+4\sqrt{10}\)

\(-a\sqrt{10}=4\sqrt{10}.........a=-4\)

OR

Make use of choices...
5, 6 and 7 can be eliminated, as the LHS will became imaginary number - squareroot of a negative number.
Now \( RHS=\sqrt{8} + \sqrt{5} \)~\(3+2=5\\
\)
\(a=-6..LHS=\sqrt{13 - a√10}=\sqrt{13 +6√10}\)~\(\sqrt{13+18}\)~6...NO
\(a=-4..LHS=\sqrt{13 - a√10}=\sqrt{13 +4√10}\)~\(\sqrt{13+12}\)~5...YES

D
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Squaring both sides we get
13- a root(10) = 13+4 root(10)
Comparing both sides we get
a = -4

OA - D

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(13−a√10) = (√8+√5)^2
13−a√10 = 8+5+2√40
a√10 = 13-13-2√40
a√10 = -2√40
a = -4
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Manasvi1
If \(\sqrt{13 - a√10} = \sqrt{8} + \sqrt{5}\), then find the value of a.

A) +5
B) -6
C) +6
D) -4
E) +7

Solution:

Squaring both sides, we have:

13 - a√10 = 8 + 5 + 2√40

-a√10 = 2√40

-a = 2√4

-a = 4

a = -4

Answer: D

Would you please explain this part?

13 - a√10 = 8 + 5 + 2√40

Thanks. :)

Explanation:

We are simply squaring each side of the equation √(13 - a√10) = √8 + √5.

The square of √(13 - a√10) is 13 - a√10. Tio find the square of √8 + √5, we have to FOIL (√8 + √5)(√8 + √5) to get:

(√8 + √5)^2

(√8)^2 + 2(√8)(√5) + (√5)^2

8 + 2√40 + 5

8 + 5 + 2√20
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