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23 Apr 2021, 11:00
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
54% (02:21) correct
46%
(02:18)
wrong
based on 13
sessions
History
Date
Time
Result
Not Attempted Yet
25 men reap a field in 20 days. when should 15 men leave work? if the whole field is to be reaped in 37-1/2 days after they leave the work?
A. 5 days
B. 10 days
C. 6 days
D. 4 days
E. 12 days
A. 5 days
B. 10 days
C. 6 days
D. 4 days
E. 12 days
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23 Apr 2021, 12:54
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Jaidude
Hello, everyone. In the interest of helping the community, I will offer my thoughts on this one.
Step #1: Calculate the total work that will go into the project.
\(25 * 20 = 500\)
500 what, you might wonder. You can think of these as man-days.
Step #2: Remove the 15 men from the crew.
\(25 - 15 = 10\)
Set this number aside, as we will need it in a minute.
Step #3: Figure out how many man-days would be completed by the full crew if each answer were true.
A. \(25 * 5 = 125\)
B. \(25 * 10 = 250\)
C. \(25 * 6 = 150\)
D. \(25 * 4 = 100\)
E. \(25 * 12 = 300\)
Step #4: Add the number of man-days for the 10-man crew to finish reaping the field in 37.5 days to each of the answers from the previous step.
A. \(125 + 10 * 37.5 = 125 + 375 = 500\)
We already know this must be the answer, since it conforms to the given information. But for fun, we can check the others.
B. \(250 + 10 * 37.5 = 250 + 375 = 625\)
\(625 > 500\)
C. \(150 + 10 * 37.5 = 150 + 375 = 525\)
\(525 > 500\)
D. \(100 + 10 * 37.5 = 100 + 375 = 475\)
\(475 < 500\)
E. \(300 + 10 * 37.5 = 300 + 375 = 675\)
\(675 > 500\)
The answer must be (A).
Of course, you could solve the question in a different manner, but this is just one approach. Good luck with your studies.
- Andrew
23 Apr 2021, 23:08
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Given: 25 men reap a field in 20 days. when should 15 men leave work?
Asked: if the whole field is to be reaped in 37-1/2 days after they leave the work?
Total work = 25*20 = 500 man-days
Man remaining = 25-15 = 10 men
Work done in 37.5 days = 375 man-days
Work done by 25 men = 125 man-days
Number of days taken by 25 men = 125/25 = 5 days
IMO A
Asked: if the whole field is to be reaped in 37-1/2 days after they leave the work?
Total work = 25*20 = 500 man-days
Man remaining = 25-15 = 10 men
Work done in 37.5 days = 375 man-days
Work done by 25 men = 125 man-days
Number of days taken by 25 men = 125/25 = 5 days
IMO A
