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30A cans can paint= W wall
30A= W...(A=W/30)

50B cans can paint= W wall
50B= W...(B=W/50)

xA and 30B cans can paint= W wall
xA+30B= W
Put values of A and B
x(W/30)+30(W/50)= W (W cancels each other)
(x/30)+(3/5)=1 (take LCM)
(5x+90)/150= 1
5x+90= 150
5x= 150-90= 60
x= 60/5 = 12

Answer: B
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30sec solution
Total A needed = 30
Also, 30A = 50B => 3A = 5B

Given 30B are available
30B = 5B*6 = 3A*6 = 18A
Remaining A or value of x = 30-18 = 12


Bunuel
30 cans of paint A or 50 cans of paint B are required to paint a wall. If x cans of paint A and 30 cans of paint B are used to paint the same wall, what is the value of X?

A. 9
B. 12
C. 15
D. 18
E. 24


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To paint the wall we either require 30 cans of paint A or 50 cans of paint B.

We are told that 30 cans of paint B are used, so we need 20 more cans of paint B to finish our work.

The ratio between paint A and paint B is 3:5, i.e. 3 cans of paint A is similar to 5 cans of paint B.
If 20 cans of paint B is required then,
3/5 = x/20

which gives, x = 12
Bunuel
30 cans of paint A or 50 cans of paint B are required to paint a wall. If x cans of paint A and 30 cans of paint B are used to paint the same wall, what is the value of X?

A. 9
B. 12
C. 15
D. 18
E. 24


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