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39,897*0.0096/198.76 is approximately

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39,897*0.0096/198.76 is approximately [#permalink]

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New post 03 Jul 2016, 11:31
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Question Stats:

62% (00:50) correct 38% (00:46) wrong based on 452 sessions

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39,897*0.0096/198.76 is approximately [#permalink]

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New post Updated on: 03 Jul 2016, 11:55
1
40000*.01/200
400/200
2
correct


Sent from my iPhone using GMAT Club Forum mobile app

Originally posted by rohitrawat9990 on 03 Jul 2016, 11:47.
Last edited by rohitrawat9990 on 03 Jul 2016, 11:55, edited 2 times in total.
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Re: 39,897*0.0096/198.76 is approximately [#permalink]

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New post 03 Jul 2016, 11:49
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Bunuel wrote:
39,897*0.0096/198.76 is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200

First scan the answer choices.
Since they're spread apart, we can estimate AGGRESSIVELY (for more on this strategy, see the video below )
(39,897)(0.0096)/198.76 ≈ (40,000)(0.01)/(200)
≈ (400)/(200)
≈ 2
Answer:



Cheers,
Brent
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Re: 39,897*0.0096/198.76 is approximately [#permalink]

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New post 04 Jul 2016, 00:11
2

40000*100/200*10000=2
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Re: 39,897*0.0096/198.76 is approximately [#permalink]

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New post 27 Oct 2016, 14:16
[39,897 x (96/10000)]/(19876/100) = [40,000 x 100]/[100 x 20,000] = 2
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Re: 39,897*0.0096/198.76 is approximately [#permalink]

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New post 27 Feb 2018, 10:08
Bunuel wrote:
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200


Approximating the given expression, we have:

(40,000 x 0.01)/200 = 400/200 = 2

Answer: C
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39,897*0.0096/198.76 is approximately [#permalink]

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New post 04 Mar 2018, 20:38
1
Bunuel wrote:
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200

\(\frac{39,897*0.0096}{198.76}\)
If moving decimal points isn't your first choice, round the numbers and use powers of 10:

40,000 = 4 * 10\(^4\)
.01 = 1 * 10\(^{-2}\)
200 = 2 * 10\(^2\)

\(\frac{(4*10^4)*(1*10^{-2})}{(2*10^2)}\)

\(\frac{(4*10^4)}{(2*10^2)*(1*10^2)}\)

\(\frac{4*10^4}{2*10^{(2+2)}}\)

\(\frac{4*10^4}{2*10^4} = 2\)

Answer C
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Re: 39,897*0.0096/198.76 is approximately [#permalink]

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New post 23 Mar 2018, 03:50
1
Bunuel wrote:
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200


:-) when we round 0.0096 ...aren't we getting 0.001 ? :)

if so then then 40000 * 0.001 = 40

so 40/200 = 0.2

why is the answer C ? :?
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39,897*0.0096/198.76 is approximately [#permalink]

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New post 23 Mar 2018, 11:30
1
dave13 wrote:
Bunuel wrote:
\(\frac{39,897*0.0096}{198.76}\) is approximately

A) 0.02
B) 0.2
C) 2
D) 20
E) 200


:-) when we round 0.0096 ...aren't we getting 0.001 ? :)

if so then then 40000 * 0.001 = 40

so 40/200 = 0.2

why is the answer C ? :?

Yikes - I had a bad typo in there. Good catch. +1

Round .0096 to .01
(We look at only one digit to the right: .009 = .01)

Now, 40,000*.01 = 400
Better? :-)
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39,897*0.0096/198.76 is approximately   [#permalink] 23 Mar 2018, 11:30
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